Question

X^2-6x-4=0,

Answer 1

Use quadratic formula since we can't factor

for 0=ax²+bx+c
$x= \frac{-b+/-\sqrt{b^2-4ac}}{2a}$

so, for
0=1x²-6x-4
a=1
b=-6
c=-4

$x= \frac{-(-6)+/-\sqrt{(-6)^2-4(1)(-4)}}{2(1)}$
$x= \frac{6+/-\sqrt{36+16}}{2}$
$x= \frac{6+/-\sqrt{52}}{2}$
$x= \frac{6+/-2\sqrt{13}}{2}$
$x= 3+/-\sqrt{13}$

the solutions are x=3+√13 and x=3-√13
or aprox
x≈6.61 and x≈-0.61