Find slope first:
m =y2-y1/x2-x1
m = 1--2/2--2
m = 3/4
Select a point, insert your slope, & put it into point slope form:
y-y1 =m(x-x1)
Your final answers are:
y-1=3/4(x-2)
OR
y+2 =3/4(x+2)
Answer:
(3,-2)
Step-by-step explanation:
Rewrite in vertex form and use this form to find the vertex
The coding of the statistic is used to make it easier to work with the large sunshine data set
- The mean of the sunshine is 3.05

- The standard deviation is approximately <u>18.184</u>
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Reason:
The given parameters are;
The sample size, n = 3.
∑x = 947
Sample corrected sum of squares, Sₓₓ = 33,065.37
The mean and standard deviation = Required
Solution:

The mean of the daily total sunshine is therefore;



- The mean ≈ 3.05

Alternatively
,
The mean of the daily total sunshine,
≈3.05

Therefore;

Therefore;
The standard deviation,
≈ <u>18.184</u>
Learn more about coding of statistic data here:
brainly.com/question/14837870