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babunello [35]
3 years ago
8

Is the function ƒ(x) = e–11x an exponential function? If so, identify the base. If not, why not?

Mathematics
1 answer:
siniylev [52]3 years ago
6 0

Answer:

Yes

y=e^{-11x}=\frac{1}{e^{11x}}=\frac{1}{e^{11}} \frac{1}{e^x}=\frac{1}{e^{11}} e^{-x}

So then we see that the base on this case is: c=\frac{1}{e^{11}} , so then our function can be considered as an exponential function.

Step-by-step explanation:

First we need to define an exponential function.

The exponential function with a base c is givn by the following expression:

f(x)=c^x, and c>0, c\neq 1 and x can be any real number.

The exponential function have always a base and a variable. The value c it's called the base and x the variable.

The exponential function is defined as:

y=e^x

And the function given by:

y=\frac{1}{e^x} is called the natural exponential function.

For our special case our function is given by:

y=e^{-11x}=\frac{1}{e^{11x}}=\frac{1}{e^{11}} \frac{1}{e^x}=\frac{1}{e^{11}} e^{-x}

So then we see that the base on this case is: c=\frac{1}{e^{11}} , so then our function can be considered as an exponential function.

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