Answer: Your answer is True.
Explanation:
Answer:
a. It is a dihybrid cross
b. 0%
c. 0%
d. 0%
e. 100%
f. 0%
g. 0%
Note: Answers are given assuming that hhRD = hhDD
Explanation:
a. The cross, HHdd x hhDD is a dihybrid cross involving two traits: fruit colour and fruit shape
2. Gametes produced in the cross are given below:
for HHdd= Hd and Hd
For hhDD = hD and hD
Offspring produced in the cross:
All HhDd, which represents white and the flattened disc-shaped fruit white since They are both dominant characters.
b. Percentage of the offspring from this cross expected to have the HHDD genotype = 0%
c. Percentage of the offspring from this cros expected to have the hhDD genotype = 0%
d. Percentage of the offspring from this cross expected to have the HhDd genotype = 0%
e. Percentage of the offspring from this cross are expected to produce white and disc-shaped fruits (HHDD or HhDD or HhDd) = 100%
f. Percentage of the offspring from this cross expected to produce white and spherical fruits (HHdd or Hhdd) = 0%
g. Percentage of the offspring from this cross expected to produce yellow and disc-shape (hhDD or hhDd) = 0%
Answer:
1. Mr. Shepherd maintain a relative constant body temperature by preventing loss of heat.
2 This process is called HOMEOSTASIS
Explanation:
Homeostasis is the process whereby living organisms maintain a stable internal environment despite changes in conditions to the external environment. It is necessary that the body undergoes this process in order to guarantee survival.
According to this question, Mr. Shepherd is at a football game on a cold day. This means that in order to maintain a stable internal temperature, the body must preserve heat in the body and prevent its loss via sweating.
The answer to this question is : <span>They tolerate both freshwater and salt water.</span>
Answer:
Solution
For figure (a)
During interval AB Velocity is +ve, so the particle is moving in +ve direction, but it is slowing down as acceleration (slope of v-7 curve) is negative.
During interval BC Particle remains at rest as the velocity is zero. Acceleration is also zero.
During interval CD Velocity is -ve, so the particle is moving in -ve direction and is speeding up as acceleration is also negative.
For figure (b),
During interval AB Particle is moving in +ve direction with constant velocity and acceleration is zero.
During interval BC Particle is moving in +ve direction as velocity is +ve, but it slows down until it comes to rest as acceleration is negative.
During interval CD Velocity is -ve so the particle is moving in -ve direction and is speeding up as acceleration is also negatived
