False because they don't have the same length and shape you know they may be triangle but the their length are different.
well, you already know an absolute value expression has a ± siblings, so let's proceed without much fuss.
![\bf |2x-5|=4\implies \begin{cases} +(2x-5)=4\implies 2x=9\implies x=\cfrac{9}{2}\\[-0.5em] \hrulefill\\ -(2x-5)=4\implies 2x-5=-4\\[1em] 2x=1\implies x=\cfrac{1}{2} \end{cases}](https://tex.z-dn.net/?f=%20%5Cbf%20%7C2x-5%7C%3D4%5Cimplies%20%20%5Cbegin%7Bcases%7D%20%2B%282x-5%29%3D4%5Cimplies%202x%3D9%5Cimplies%20x%3D%5Ccfrac%7B9%7D%7B2%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20-%282x-5%29%3D4%5Cimplies%202x-5%3D-4%5C%5C%5B1em%5D%202x%3D1%5Cimplies%20x%3D%5Ccfrac%7B1%7D%7B2%7D%20%5Cend%7Bcases%7D%20)
Option I: 10 candy bars for $6.75
<span>6.75/10 = 0.68 </span>
<span>Option II: 12 candy bars for $7.25 </span>
<span>7.25 / 12 = 0.60 </span>
<span>Example<span>Problem<span><span>Use elimination to solve the system.</span> x –<span> y = </span>−6x <span>+ y = 8</span></span> </span><span> Add the equations.</span><span> <span><span>2x = 2</span>x = 1</span><span>Solve for x.</span></span><span> <span>x<span> + y = 8</span><span>1 + y = 8</span>y = 8 – 1y = 7</span><span>Substitute x = 1 into one of the original equations and solve for y.</span></span><span> <span>x<span> – y = −6</span>1 – 7 = −6−6 = −6 TRUE</span><span>x<span> + y = 8</span>1 + 7 = 88 = 8TRUE</span><span>Be sure to check your answer in both equations!</span></span><span>AnswerThe solution is (1, 7). </span></span>
Answer:
42
Step-by-step explanation:
The formula for area is length multiplied by width
7 X 6 = 42
hope this helps :)
