Answer:
-79, -55, 18, 44, 101, 143
Step-by-step explanation:
I would say the first one because it goes into more detail than just 8x2=16 it would be like me saying "I have a dog" and then "i have a dog that can do tricks" witch one would you chose for more details
The shape of my field is an <u>oval</u>
It's<u> oval</u> rather than round because I have two eyes, and each has a separate field like the one pictured here. Putting them together creates an oval. So if you wanted to represent what I can see, you would take a wide-angle photo from my vantage point and cut out a roughly oval shape
Therefore, the shape of my field is an <u>oval</u>
Answer:
The probability is 0.0052
Step-by-step explanation:
Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:
P(A/B) = P(A∩B)/P(B)
The probability P(B) that at least three are aces is the sum of the following probabilities:
- The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
- There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

So, the number of ways to select exactly 3 aces is:

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725
Then, the probability P(B) that at least three are aces is:

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:
P(A∩B) = 1/270,725
Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

Simplify
9x^3 - 4x + 10 + x^3 + 10x - 9
Collect like terms
(9x^3 + x^3) + (-4x + 10x) + (10 - 9)
Simplify
<u>10x^2 + 6x + 1</u>