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meriva
2 years ago
12

What is the ratio of oranges to apples? Write it as a fraction?

Mathematics
1 answer:
Iteru [2.4K]2 years ago
3 0

Answer:

See below.

Step-by-step explanation:

3.)

There are 4 oranges and 6 apples so the fraction would be 4/6 which we can reduce to 2/3.

a.) As we stated beforehand, the fraction was 2/3. That means for every 2 oranges, there are 3 apples.

b.) We did this already. 4/6 was reduced to 2/3.

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Least to greatest <br> -55,143,18,-79,44,101
katovenus [111]

Answer:

-79, -55, 18, 44, 101, 143

Step-by-step explanation:

3 0
3 years ago
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1/8 divided by 2 = 1/16
kati45 [8]
I would say the first one because it goes into more detail than just 8x2=16 it would be like me saying "I have a dog" and then "i have a dog that can do tricks"  witch one would you chose for more details
5 0
3 years ago
What shape is your field of vision?
Nat2105 [25]

The shape of my field is an <u>oval</u>

It's<u> oval</u> rather than round because I have two eyes, and each has a separate field like the one pictured here. Putting them together creates an oval. So if you wanted to represent what I can see, you would take a wide-angle photo from my vantage point and cut out a roughly oval shape

Therefore, the shape of my field is an <u>oval</u>

6 0
2 years ago
Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
3 years ago
Simplify (9x^3-4x+10)+(x^3+10x-9)
Alex

Simplify

9x^3 - 4x + 10 + x^3 + 10x - 9

Collect like terms

(9x^3 + x^3) + (-4x + 10x) + (10 - 9)

Simplify

<u>10x^2 + 6x + 1</u>

6 0
3 years ago
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