Question

When a store had Sold 2/5 of the shirts that were on display, they brought out another 30 from the stockroom. The store likes to keep at least a 150 shirts on display. The manager wrote the inequality 3/5× + 30 >_ 150 to describe the situation.
A. explain what 3/5 means in the in equality.
B. Solve the in equality.
C.explain what the solution means in the situation.

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Answer 1

Answer:

Part A) 3/5 is the total number of shirts remaining on display after selling 2/5

Part B) $x \geq 200$ (All real whole numbers greater than or equal to 200 shirts)

Part C) Initially on display were the amount of 200 or more shirts

Step-by-step explanation:

Let

x-------> total number of shirts on display

we know that

The inequality that represent the situation is

$(1-\frac{2}{5})x+30 \geq 150$

$(\frac{3}{5})x+30 \geq 150$

Part A)  Explain what 3/5 means in the inequality

3/5 is the total number of shirts remaining on display after selling 2/5

Part B) Solve the inequality

we have

$(\frac{3}{5})x+30 \geq 150$

Subtract 30 both sides

$(\frac{3}{5})x \geq 150-30$

$(\frac{3}{5})x \geq 120$

Multiply by 5/3 both sides

$x \geq 120(5/3)$

$x \geq 200\ shirts\ on\ display$

Part C) Explain what the solution means in the situation

1) Initially on display were the amount of 200 or more shirts

2) 2/5 were sold and 120 or more shirts were left on display.

3) The store brought out another 30 shirts from the stockroom and placed them on display, for a total of 150 shirts or more on display