Answer: 20 km
Step-by-step explanation: Let's assume a trajectory of Ships A (which is moving at 6 km/h) and B (which is moving at 4 km/h)
__________________
A 10 km B
And let's assume that who is going to the right is the positive.
Space (S) = S₀ + vt
For A, its space is SA = 0 + 6t
For B, its space is SB = 10 - 4t
They meet at SA = SB;
6t = 10 - 4t
6t + 4t = 10
10t = 10
t = 1h
If the bird is at 20 km/h and it will fly for 1h, it will travel 20 km
Answer:
distance = 9.25
4 days a week = 16 days a month
9.25 × 16 = 148 miles.
The answer is 148 miles.
Hope it helps :)
Answer:
Negative
Step-by-step explanation:
The answer is D. If you were to add by four each time like Madison, you would get 4, 8,12, 16, 20, and so forth. If you add by 12, you would get 12, 24, 36, 48, and 60 and so on. Looking at the first two numbers, 12 is three times the number 4. Such is true for the next two corresponding numbers. 8 x 3 = 24. You would find this to be true for all the corresponding numbers, therefore Pedro's numbers will be three times Madison's numbers, so the right answer is D.