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KIM [24]
3 years ago
8

Explain why solving (2/5)c = (8/9) by multiplying both sides by (5/2) is the same as solving it by dividing both sides by (2/5)

Mathematics
1 answer:
givi [52]3 years ago
3 0
Dividing by a fraction is the same as multiplying by its reciprocal. So dividing by 2/5 will give you the same answer as multiplying by 5/2.
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3 1/2 × 1 1/2 × 2 =​
andrey2020 [161]

Answer:

38.5

Step-by-step explanation:

4 0
3 years ago
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BRANILIEST OFFER!!what is the median of this data set?<br> 25, 8, 10, 35,45, 5, 40, 30. 20.
ivann1987 [24]
Median is the middle of the number set so
5 8 10 20 25 30 35 40 45
its 25

4 0
4 years ago
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Find, correct to four decimal places, the length of the curve of intersection of the cylinder 16x2 + y2 = 16 and the plane x + y
Yuri [45]

Let the curve C be the intersection of the cylinder  



16x^2+y^2=16



and the plane



x+y+z=1



The projection of C on to the x-y plane is the ellipse



16x^2+y^2=16



To see clearly that this is an ellipse, le us divide through by 16, to get



\frac{x^2}{1}+ \frac{y^2}{16}=1



or  



\frac{x^2}{1^2}+ \frac{y^2}{4^2}=1,



We can write the following parametric equations,



x=cos(t), y=4sin(t)



for  



0\le t \le 2\pi



Since C lies on the plane,



x+y+z=1



it must satisfy its equation.



Let us make z the subject first,  



z=1-x-y



This implies that,



z=1-sin(t)-4cos(t)



We can now write the vector equation of C, to obtain,



r(t)=(cos(t),4sin(t),1-cos(t)-4sin(t))



The length of the curve of the intersection of the cylinder and the plane is now given by,



\int\limits^{2\pi}_0 {|r'(t)|} \, dt



But  



r'(t)=(-sin(t),4cos(t),sin(t)-4cos(t))



|r'(t)|=\sqrt{(-sin(t))^2+(4cos(t))^2+(sin(t)-4cos(t))}



\int\limits^{2\pi}_0 {\sqrt{2sin^2(t)+32cos(t)-8sin(t)cos(t)} }\, dt=24.08778184



Therefore the length of the curve of the intersection  intersection of the cylinder and the plane is 24.0878 units correct to four decimal places.

6 0
3 years ago
Suppose that IQ scores have a bell-shaped distribution with a mean of 104 and a standard deviation of 17. Using the empirical ru
Shalnov [3]

Answer:

By the Empirical Rule, 68% of IQ scores are between 87 and 121

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 104

Standard deviation = 17

Using the empirical rule, what percentage of IQ scores are between 87 and 121

87 = 104 - 1*17

So 87 is one standard deviation below the mean

121 = 104 + 1*17

So 121 is one standard deviation above the mean

By the Empirical Rule, 68% of IQ scores are between 87 and 121

4 0
4 years ago
Given n &gt; 0, Adam conjectured that 6" Which value is a counterexample to Adam's conjecture?
miv72 [106K]

Answer:

n = 4

Step-by-step explanation:

Unit: 1.14 Unit Test: Introduction to Logic and Euclidean Geometry - Part 1

5 0
2 years ago
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