Answer:
<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>
Step-by-step explanation:
Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:
<h3>To find how many imaginary roots does the polynomial have :</h3>
- Since the degree of given polynomial is 4
- Therefore it must have four roots.
- Already given that the given polynomial has 1 positive real root and 1 negative real root .
- Every polynomial with degree greater than 1 has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>
Answer:
10
Step-by-step explanation:
x = Edith's age = 20 years
y = Ronald's age
x = 20 = y/4
y = 20×4 = 80 years
in z years we have
(x + z) = (y + z)/3
(20 + z) = (80 + z)/3
3(20 + z) = 80 + z
60 + 3z = 80 + z
60 + 2z = 80
2z = 20
z = 10
in 10 years Edith's age will be 1/3 of Ronald's age.
then Edith will be 30, and Ronald will be 90.
30 = 90/3
correct.
Answer:x=20/y
Step-by-step explanation:
x α 1/y
removing the constant of proportionality sign α and replace it with =k
x = k/y
x=10 y=2
10 = k/2
Cross multiply
10x2=k
20=k
k=20
Substitute k=20 in x=k/y
x=20/y.........required equation
Answer:
-1
Step-by-step explanation:
The constant rate of change is -y for every one x.
6(4)^2 + 2
= 6(16) + 2
= 96 + 2
= 98
