Y= 175÷x+z when x=17 and z=8

What is the answers to this

mash [69]

Answers to what exactly?

3 0

2 years ago

Oliver deposits $1,000 in his Interest-bearing bank account. The balance increases by %15 each month

Volgvan

Step-by-step explanation:

Oliver deposits P= $1,000

Then total amount A after n months given that the balance increases by %15 each month can be calculated as

$A= 1000(1+15/100)^n$

Assuming the increase in amount is compounded monthly.

5 0

2 years ago

A shark is at -80 feet. It swims up and jumps out of the water to a height of 15 feet. Write a subtraction expression for the ve

lilavasa [31]

Since the shark is in a deep water level of specifically 80 feet it is then represented by a negative coefficient. This is due to the vector quantity the measure represents as decelerating or sinking or downward in direction. As oppose the shark moves upward with a height of 15ft.
Thus the expression will be -80ft + 15 ft = -65ft is the displacement.
15ft is positive since the movement is upward and the displacement then from the origin to the point of last position is 65ft, negative.

3 0

3 years ago

Which equation represents the graph below

andreyandreev [35.5K]

Answer: b. -2x+3y=12

Step-by-step explanation: the y intercept is 4, and the line intercepts the x- axis at -6. Therefore, the slope of the line is 4/6=2/3. The format for a linear equation is y=(slope)x+y intercept. So the equation would be y=2/3x+4. You can see that answer b simplifies to that. Add 2x from both sides of the equation and you get 3y=2x+12. Divide both sides of the equation by 3 and you get y=2/3x+4

8 0

2 years ago

What is the range of the following function:<br> y = 2(5^x) - 1

Orlov [11]

<h2>Hello!</h2>

The answer is:

The range of the function is:

Range: y>2

or

Range: (2,∞+)

To calculate the range of the following function (exponential function) we need to perform the following steps:

First: Find the value of "x"

So, finding "x" we have:

$y=2(5^{x}-1)\\\frac{y}{2}=5^{x}-1\\\\\frac{y}{2}-1=5^{x}\\\\Log_{5}(\frac{y}{2}-1)=Log_5(5^{x})\\\\x=Log_{5}(\frac{y}{2}-1)$

Second: Interpret the restriction of the function:

Since we are working with logarithms, we know that the only restriction that we found is that the logarithmic functions exist only from 0 to the possitive infinite without considering the number 1.

So, we can see that if the variable "x" is a real number, "y" must be greater than 2 because if it's equal to 2 the expression inside the logarithm will tend to 0, and since the logarithm of 0 does not exist in the real numbers, the variable "x" would not be equal to a real number.

Hence, the range of the function is:

Range: y>2

or

Range: (2,∞+)

Note: I have attached a picture (the graph of the function) for better understanding.

Have a nice day!

5 0

2 years ago