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bazaltina [42]
3 years ago
6

If your teacher tells you to do questions 28 through 41 in your math book for homework, how many questions is that?

Mathematics
2 answers:
ANTONII [103]3 years ago
5 0
41-28=13 questions, but you also have to do 41 and 28, so 15 questions
klasskru [66]3 years ago
3 0

Answer:

14 questions.

Step-by-step explanation:

We have been given that your teacher tells you to do questions 28 through 41 in your math book for homework. We are asked to find he total number of questions.

Since we need to solve questions 28 through 41, this means we have to solve question number 28 and 41 as well.

We know that 28-37 would be 10 questions and 38-41 would be 4 questions.

\text{Total questions}=10+4

\text{Total questions}=14

Therefore, you need to solve 14 questions to complete the homework.

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$29.00 and you can also multiply too is is a cool way
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Q.2. Separate the digits of the number "893451" as per National and
LuckyWell [14K]

Answer:

imm a bit sorry I could only answer the international one as the national is equal to international place value system

Step-by-step explanation:

eight hundred ninety three thousand four hundred fifty one

hth tth th h t o

8 9 3 4 5 1

I hope you understand

8 0
3 years ago
I need to convert x^2 +6x-16 to vertex form with steps listed please
Naddika [18.5K]
What steps are listed?
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4 years ago
Suppose that p is the probability that a randomly selected person is left handed. The value (1-p) is the probability that the pe
solmaris [256]

Answer:

a) 1/2

b) 250

Step-by-step explanation:

The start of the question doesn't matter entirely, although is interesting to read. What we are trying to do is find the value for p such that 1000p(1-p) is maximized. Once we have that p, we can easily find the answer to part b.

Finding the value that maximizes 1000p(1-p) is the same as finding the value that maximizes p(1-p), just on a smaller scale. So, we really want to maximize p(1-p). To do this, we will do a trick called completing the square.

p(1-p)=p-p^2=-p^2+p=-(p^2-p)=-(p^2-p+1/4)-(-1/4)=-(p-1/2)^2+1/4.

Because there is a negative sign in front of the big squared term, combined with the fact that a square is always positive, means we need to find the value of p such that the inner part of the square term is equal to 0.

p-1/2=0\\p=1/2.

So, the answer to part a is \boxed{1/2}.

We can then plug 1/2 into the equation for p to find the answer to part b.

1000(1/2)(1-1/2)=1000(1/2)(1/2)=1000*1/4=250.

So, the answer to part b is \boxed{250}.

And we're done!

3 0
3 years ago
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population pro
Gnom [1K]

Answer:

A sample of 1068 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?

We need a sample of n.

n is found when M = 0.03.

We have no prior estimate of \pi, so we use the worst case scenario, which is \pi = 0.5

Then

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.03}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.03})^{2}

n = 1067.11

Rounding up

A sample of 1068 is needed.

8 0
3 years ago
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