If similarity ratio means the ratio between the lengths of the cubes:
![\frac{ L_1^{3} }{ L_2^{3} } = \frac{V_1}{V_2} \\ \\ ratio = \frac{L_1}{L_2} = \frac{\sqrt[3]{V_1} }{\sqrt[3]{V_2} }](https://tex.z-dn.net/?f=%5Cfrac%7B%20L_1%5E%7B3%7D%20%7D%7B%20L_2%5E%7B3%7D%20%7D%20%3D%20%20%5Cfrac%7BV_1%7D%7BV_2%7D%20%20%5C%5C%20%20%5C%5C%20ratio%20%3D%20%20%5Cfrac%7BL_1%7D%7BL_2%7D%20%3D%20%20%20%5Cfrac%7B%5Csqrt%5B3%5D%7BV_1%7D%20%7D%7B%5Csqrt%5B3%5D%7BV_2%7D%20%7D%20)
Triangle ABC is similar to triangle DEF. The length of AC is 10cm. The length of BC is 16 cm. The length of DF is 8cm. What is t
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Answer:
Step-by-step explanation:
To solve this problem you must apply the proccedure shown below:
- Apply the Distributive property.
- Remember that, according the exponents properties, when you multiply two powers with equal base, you must add the exponents.
- Add the like terms.
Therefore, you obtain that the product is the following:
Find the attached image.
