Question

I WILL UPVOTE

Answer 1

Given that y =c(x)=^3√x . solving for the value of y for x = 0, 0.008, 0.027, 0.064, 0.125, 0.216, 0.343, 0.512, 0.729, and 1. The value of y with its corresponding x are:

X             y

0              0

0.008     0.2

0.027     0.3

0.064     0.4

0.125     0.5

0.216     0.6

0.343     0.7

0.512     0.8

0.729     0.9

1              1

Answer 2

Step-by-step explanation:

We are given a function as:

$y=c(x)=\sqrt[3]{x}$

We have to find the value of the function at different values of x:

1)

when x=0

$y=\sqrt[3]{0}\\\\y=0$

Hence, y=0

2)

when x=0.008

$y=\sqrt[3]{0.008}\\\\y=\sqrt[3]{(0.2)^3}\\\\y=0.2$

Hence y=0.2

3)

when x=0.027

$y=\sqrt[3]{0.027}\\\\y=\sqrt[3]{(0.3)^3}\\\\y=0.3$

Hence, y=0.3

4)

when x=0.064

$y=\sqrt[3]{0.064}\\\\y=\sqrt[3]{(0.4)^3}\\\\y=0.4$

Hence, y=0.4

5)

when x=0.125

$y=\sqrt[3]{0.125}\\\\y=\sqrt[3]{(0.5)^3}\\\\y=0.5$

Hence, y=0.5

6)

when x=0.216

$y=\sqrt[3]{0.216}\\\\y=\sqrt[3]{(0.6)^3}\\\\y=0.6$

Hence, y=0.6

7)

when x=0.343

$y=\sqrt[3]{0.343}\\\\y=\sqrt[3]{(0.7)^3}\\\\y=0.7$

Hence, y=0.7

8)

when x=0.512

$y=\sqrt[3]{0.512}\\\\y=\sqrt[3]{(0.8)^3}\\\\y=0.8$

Hence, y=0.8

9)

when x=0.729

$y=\sqrt[3]{0.729}\\\\y=\sqrt[3]{(0.9)^3}\\\\y=0.9$

Hence, y=0.9

10)

when x=1

$y=\sqrt[3]{1}\\\\y=\sqrt[3]{(1)^3}\\\\y=1$

Hence, y=1