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3 years ago

I need to do this tonight, help plz

Mathematics

1 answer:

sammy [17]3 years ago

4 0

The intercepts are where the function graph crosses an axis. For example, your x-intercept is (5,0) because the function crosses the x-axis at this point. The y-intercepts are (0, +/- 1.5). The domain is whatever x-coordinates are crossed, in this case, -3 < x </= 5. The range includes any y-coordinates that are crossed. -2 < y < 2.

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The ratio of men to women working for a company is 2 to 3 . If there are 120 employees total, how many women work for the compan

gtnhenbr [62]

I think the answer is 20

3 0

4 years ago

Why do we use variables in math?

Phoenix [80]

Answer:

We use it to substitute an unknown number. We have a variable for a number we don’t know and as we solve the problem we can find the answer for the variable or unknown number.

Step-by-step explanation:

I hope it helps! Have a great day!
Anygays-

8 0

2 years ago

Read 2 more answers

following frequency distribution shows the daily expenditure on milk of 30 households in a locality:Daily expenditure on milk(in

valina [46]

Note: As you missed to identify what we have to find in this question. But, after a little research, I am able to find that we had to find the Mode for the data given in your question. So, I am assuming we have to calculate the the Mode. Hopefully, it would clear your concept regarding this topic.

Answer:

The mode of the data = 75

Step-by-step explanation:

Lets visualize the given data in a table to show the frequency distribution:

Daily expenditure on milk (in Rs) Number of households

0-30 5

30-60 6

60-90 9

90-120 6

120-150 4

Here the maximum frequency is 9.

So, modal class is 60-90.

As the formula to calculate the mode:

$Mode = l_{1} + h (\frac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}} )$

Here, the maximum

$l_{1} =60, f_{1} =9, f_{0}=6, f_{0}=6, h=30$

$l=$ is the lower limit of the class

$f_{1} =$ is the frequency of the modal class

$f_{0} =$ is the frequency of the previous modal class

$f_{2} =$ is the frequency of the next previous modal class

$l=$ is the class size

So,

$Mode = l_{1} + h (\frac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}} )$

$Mode = 60 + 30 (\frac{9-6}{2(9)-6-6} )$

$Mode = 60 + \frac{(30)(3)}{6}$

$Mode = 60 + 15=75$

∴ The mode of the data = 75

Keywords: mode, frequency distribution

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5 0

3 years ago

tavon has a $15 gift card that lose $3 for 30- day period It is not used. he has a $40 that loses $1.50 for each day period it i

Anna11 [10]

The number of 30- period until the value if the give card be equal is 20 30- day period

<h3>How to write and solve equation</h3>

let

Number of 30- day period = x

Card 1:

50 - 2x

Card 2:

40 - 1.50x

50 - 2x = 40 - 1.50x

50 - 40 = -1.50x + 2x

10 = 0.50x

divide both sides by 0.50

x = 10/0.50

x = 20

In conclusion, it will take 20 30- day period until the value of the given card can be equal.

Complete question:

Tavon has a $50 gift card that loses $2 for each 30-day period it is not used. He has a $40 card that loses $1.50 for each 30-day period it is not used.