Answer:
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Complete question is;
A skull cleaning factory cleans animal skulls and other types of animals using flesh eating Beatles. The factory owner started with only 13 adult beetles.
After 35 days, the beetle population grew to 26 adult beetles. How long did it take before the beetle population was 13,000 beetles?
Answer:
349 days.
Step-by-step explanation:
We are given;
Initial amount of adult beetles; A_o = 13
Amount of adult beetles after 35 days; A_35 = 26
Thus can be solved using the exponential formua;
A_t = A_o × e^(kt)
Where A_t is the amount after time t, t is the time and k is a constant.
Plugging in the relevant values;
26 = 13 × e^(35k)
e^(35k) = 26/13
e^(35k) = 2
35k = In 2
35k = 0.6931
k = 0.6931/35
k = 0.0198
Now,when the beetle population is 12000,we can find the time from;
13000 = 13 × e^(k × 0.0198)
e^(k × 0.0198) = 13000/13
e^(k × 0.0198) = 1000
0.0198k = In 1000
0.0198k = 6.9078
k = 6.9078/0.0198
k ≈ 349 days.
Answer: 1440
Step-by-step explanation:
To arrange 3 boys and 4 girls such that no two boys are together.
Since boys should be arranged between the girls.
So first arrange the girls.
Assume that the girls are placed, then there will be 5 spaces left for 3 boys.
The number of combinations to fill these places = 
Also, 3 boys can arrange themselves in 3! =3 x 2 x 1 = 6 ways
4 girls can arrange themselves in 4! = 4x 3 x 2 x 1 = 24 ways
Then, the total number of arrangements = 10 x 6 x 24 = 1440
Hence, the required number of arrangements = 1440
Answer:
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Step-by-step explanation:
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