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Rashid [163]
2 years ago
6

25 POINTS! What is the distance between the points (2, 3) and (5, -4)? (XY AXIS)

Mathematics
2 answers:
JulijaS [17]2 years ago
8 0
A=(2,3)\qquad\qquad B=(5,-4)\\\\\\d(A,B)=\sqrt{(5-2)^2+(-4-3)^2}=\sqrt{3^2+(-7)^2}=\sqrt{9+49}=\\\\=\boxed{\sqrt{58}\approx7.61}
Finger [1]2 years ago
4 0
The distance could be calculated as follows:
d = \sqrt{ (5-2)^{2}  +  (-4-3)^2}  }
d = \sqrt{ 3^{2} + (-7)^{2}
d = \sqrt{58}
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8 0
3 years ago
Pls help me with this problem!!!!
kolbaska11 [484]

Answer: 55°

Step-by-step explanation:

∠YAZ + ∠YAX = 180° because they are linear pairs

∠YAZ + ∠YAX = 180°

∠YAZ + 125 = 180

Subtract both sides by 125

∠YAZ = 55°

Hope that helped!

8 0
2 years ago
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