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Rashid [163]
3 years ago
6

25 POINTS! What is the distance between the points (2, 3) and (5, -4)? (XY AXIS)

Mathematics
2 answers:
JulijaS [17]3 years ago
8 0
A=(2,3)\qquad\qquad B=(5,-4)\\\\\\d(A,B)=\sqrt{(5-2)^2+(-4-3)^2}=\sqrt{3^2+(-7)^2}=\sqrt{9+49}=\\\\=\boxed{\sqrt{58}\approx7.61}
Finger [1]3 years ago
4 0
The distance could be calculated as follows:
d = \sqrt{ (5-2)^{2}  +  (-4-3)^2}  }
d = \sqrt{ 3^{2} + (-7)^{2}
d = \sqrt{58}
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4 0
3 years ago
write an equation in slope intercept form of a line passing through the point (2,-3) that is perpendicular to a line whose slope
vladimir2022 [97]
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6 0
3 years ago
What facts are required in order to conclude that m∠ADE = m∠ABC?
mariarad [96]

Answer:

The correct option is;

DE = 2·(BC), AD = 2·(AB), and AE = 2·(AC)

Step-by-step explanation:

Given that we have;

1) The side AD of the angle m∠ADE corresponds to the side AB of the angle m∠ABC

2) The side DE of the angle m∠ADE corresponds to the side BC of the angle m∠ABC

3) The side AE of the angle m∠ADE corresponds to the side AC of the angle m∠ABC

Then when we have DE = 2·(BC), AD = 2·(AB), and AE = 2·(AC), we have by sin rule;

AE/(sin(m∠ADE)) = 2·(AC)/(sin(m∠ABC)) = AE/(sin(m∠ABC))

∴ (sin(m∠ADE)) = (sin(m∠ABC))

m∠ADE) = m∠ABC).

3 0
3 years ago
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defon

Answer:

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Step-by-step explanation:

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