25 POINTS! What is the distance between the points (2, 3) and (5, -4)? (XY AXIS)

2 answers:

8 0

$A=(2,3)\qquad\qquad B=(5,-4)\\\\\\d(A,B)=\sqrt{(5-2)^2+(-4-3)^2}=\sqrt{3^2+(-7)^2}=\sqrt{9+49}=\\\\=\boxed{\sqrt{58}\approx7.61}$

Finger [1]3 years ago

4 0

The distance could be calculated as follows:
d = $\sqrt{ (5-2)^{2} + (-4-3)^2} }$
d = $\sqrt{ 3^{2} + (-7)^{2}$
d = $\sqrt{58}$

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