Step-by-step explanation:
C. n 1 2 3 4
an 3 6 9 15
hope this helps you
have a great day : )

Explanation:

let's break down the expression to get the final result:

Answer:
Step-by-step explanation:
AB and DC are parallel, so ∠B and ∠C are supplementary angles.
∠B = 180°-∠C = 79°
AD and BC are congruent. ∠A = ∠B = 79°
We can create two equations here:
(1) Volume = area of square * height of box
85.75 = s^2 h
(2) Cost = 3 * area of square + 1.5 * area of side box
C = 3 s^2 + 1.5 s h
From (1), we get:
h = 85.75 / s^2
Combining this with (2):
C = 3 s^2 + 1.5 s (85.75 / s^2)
C = 3 s^2 + 128.625 s-
Taking the 1st derivative and equating dC/ds =
0:
dC/ds = 6s – 128.625 / s^2 = 0
Multiply all by s^2:
6s^3 – 128.625 = 0
6s^3 = 128.625
s = 2.78 cm
So h is:
h = 85.75 / s^2 = 85.75 / (2.78)^2
h = 11.10 cm
So the dimensions are 2.78 cm x 2.78 cm x 11.10 cm
The total cost now is:
C = 3 (2.78)^2 + 1.5 (2.78) (11.10)
C = $69.47
Answer:
D
Step-by-step explanation:
A polynomial in standard form has the terms in ascending order.
In other words, the term with the largest degree is on the left, followed by the term with the second largest degree, etc.
The largest term in this polynomial is 2x³. Thus, we need to start with that.
The only choice that starts with 2x³ is choice D.
Thus, choice D is in standard form.
And examining choice D, we see that it is in ascending order all the way through.