Answer:
0.57142
Step-by-step explanation:
A normal random variable with mean and standard deviation both equal to 10 degrees Celsius. What is the probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit?
We are told that the Mean and Standard deviation = 10°C
We convert to Fahrenheit
(10°C × 9/5) + 32 = 50°F
Hence, we solve using z score formula
z = (x-μ)/σ, where
x is the raw score = 59 °F
μ is the population mean = 50 °F
σ is the population standard deviation = 50 °F
z = 59 - 50/50
z = 0.18
Probability value from Z-Table:
P(x ≤59) = 0.57142
The probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit
is 0.57142
Answer:
B. -3d + 47.25
Step-by-step explanation:
Each of them has $15.75
Each spent $d
Amount each still has = 15.75 - d
Therefore, total amount the 3 of them has = 3(15.75 - d) = 3*15.75 - 3*d
= 47.25 - 3d
Which is also am equivalent of -3d + 47.25
Answer:
your answer is gonna be 579 miles that would be your answer
Answer: (6,16)
(6,2)
(-2,8)
(14,8)
