i think it is 2.x5
Step-by-step explanation:
The first five terms of the recursively defined sequence are 6, 12, 48, 768, 196608
For given question,
We have been given the recursive formula of a sequence.

Also, the first term of the sequence is,
a1 = 6
Substitute k = 1 in given recursive formula.
⇒ 
⇒ a2 = 1/3 (6)²
⇒ a2 = (1/3) × 36
⇒ a2 = 12
Substitute k = 2 in given recursive formula.
⇒ 
⇒ a3 = (1/3) × (12)²
⇒ a3 = (1/3) × 144
⇒ a3 = 48
Substitute k = 3 in given recursive formula.
⇒ 
⇒ a4 = (1/3) × (48)²
⇒ a4 = (1/3) × 2304
⇒ a4 = 768
Substitute k = 4 in given recursive formula.
⇒ 
⇒ a5 = (1/3) × (768)²
⇒ a5 = (1/3) × 589824
⇒ a5 = 196608
Therefore, the first five terms of the recursively defined sequence are 6, 12, 48, 768, 196608
Learn more about the recursive formula of sequence here:
brainly.com/question/14457800
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8n+16
the four odd numbers are 2n+1, 2n+3, 2n+5, 2n+7
2n+1+2n+3+2n+5+2n+7=8n+16
Answer:
x = -1
Step-by-step explanation:
1.1 Pull out like factors :
-2x - 2 = -2 • (x + 1)
2.1 Solve : -2 = 0
x = -1
Answer:
A
Step-by-step explanation:
Given
(3x² - 11x - 4) - (2x² - x - 6)
Distribute both parenthesis, noting the second is distributed by - 1
= 3x² - 11x - 4 - 2x² + x + 6 ← collect like terms
= x² - 10x + 2 ← this is a quadratic with 3 terms, thus trinomial → A