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3 years ago

Developing it says constructing equations from a table

Mathematics

1 answer:

12345 [234]3 years ago

7 0

The equation is y=2x+1.
to find b in y=mx+b you simply look for a point where x=0 which was (0,1) making the y-intercept or "b" equal to 1. to find the "m" or slope plug in any point for x and y. (9)=m(4)+1 is 2=m. so y=2x+1 is your answer.

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F(x)= -2x^2<br>what is the vertex of this and/or how do you find the vertex??

Doss [256]

Answer:

(0,0)

Step-by-step explanation:

x value of vertex = -b/2a

ax^2+bx+c

-2x^2+0x+0 sinc you have no value of b & c in your quadratic function

-b = 0

2a = (2)(-2)

-b/2a = (0/-4) = 0

x value of the vertex = 0

plug 0 in for all values of x in the function to find y coordinate value

-2(0)^2 = 0

(x,y) = (0,0)

7 0

2 years ago

What is the equation for the line? Enter your answer in the box

Ipatiy [6.2K]

y=-1/2x-4

I could be wrong. Not my strong subject.

-Seth

4 0

3 years ago

Any mha fans.............................

lidiya [134]

Answer:

you bet

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

For online courses, like those in eCore, there is a positive correlation between the amount of time spent in the course and the

Troyanec [42]

Answer:

Regression Line is given by,

y = 22.909 + 0.209 x

The course grade of a student in the course who spent an average of 103 minutes in the course each week is: 22.909 + 0.209 × 103 = 44.436

Step-by-step explanation:

The equation of Regression equation is of the form of:

y = a + bx

where, a is intercept and b is slope

The formula for a and b is given by,

$a=\frac{\sum Y \sum X^2-\sum X \sum XY}{n\sum X^2-(\sum X)^2}\\ and, b = \frac{n\sum XY -\sum X \sum Y}{n\sum X^2-(\sum X)^2}$

Here, ∑X = 1149.8, ∑Y = 377.2, ∑XY = 93115.95, ∑X² = 320246.72

Thus, a = 22.909

and b = 0.209

Thus, Regression Line is given by,

y = 22.909 + 0.209 x

Thus, The course grade of a student in the course who spent an average of 103 minutes in the course each week is: 22.909 + 0.209 × 103 = 44.436

Now plotting these line:

6 0

3 years ago

A jogger goes 1.5km west and then turns south.If the jogger finishes 1.7 km from the starting point,how far south did the jogger

kakasveta [241]

Hello!

You can use the Pythagorean Theorem to solve this

$a^{2} + b^{2} = c^{2}$

c is the hypotenuse
a and b are the legs

Put in the values you know

$1.5^{2} + b^{2} = 1.7^{2}$

Square the numbers

$2.25+ b^{2} =2.89$

Subtract 2.25 from both sides

$b^{2} =0.64$

Take the square root of both sides

b = 0.8

The answer is 0.8km

Hope this helps!

6 0

3 years ago