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olga2289 [7]
3 years ago
5

Subtract (2x²+5) - (4x - 3)

Mathematics
2 answers:
Ivahew [28]3 years ago
3 0

Answer:

                  x = -1

Step-by-step explanation:

1.1     Pull out like factors :

  -2x - 2  =   -2 • (x + 1)

2.1      Solve :    -2   =  0

x = -1

Tpy6a [65]3 years ago
3 0

Answer: 2x^2 - 4x + 8

Step-by-step explanation:

The first step to solving this equation will be to distribute the negative sign to the 4x and the -3 in parenthesis.

-1(4x - 3) = -4x + 3

We now have the equation:

2x^2 + 5 -4x + 3

Combine like terms:

2x^2 - 4x + 8

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What two numbers have an absolute value of 16
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The two numbers are 16 and -16.
They both have the same absolute value, 16.


7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%20%7D%20%20%5Ctimes%20%20%5Cfrac%7B5%7D%7B7%7D%20%20%5Ctimes%20%20%5Cfra
VikaD [51]

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Step-by-step explanation:

5 0
3 years ago
If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

4 0
2 years ago
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