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3 years ago

Find an ordered triple to represent a in the equation a=2g-5f if f=(1,-3,-8) and g=(3,9,-1)

Mathematics

2 answers:

pshichka [43]3 years ago

6 0

Answer:

(1,33,38)

Step-by-step explanation:

got right on edg

ollegr [7]3 years ago

3 0

Answer:

^B edge

Step-by-step explanation:

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What is 50.605 in simplest form

Mumz [18]

Put the 50.605 over 1 then multiply by 1 to eliminate the decimal then multiply the numerator and denominator by 10^3=1000. Find the GCF which is 5 and divide the numerator and denominator by 5 then simplify the improper fraction

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3 years ago

topjm [15]

What even is this lol

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3 years ago

You roll a number cube twice. What is the probability of rolling a 2 first and then rolling an odd number?

nevsk [136]

So i believe the answer is d) 1/9

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3 years ago

Is f(x)=3x5^2x-3 an exponential function? If so, write it in the form f(x)=ab^x

Anna11 [10]

Answer:

$f(x)=\frac{3}{125} * 25^x$

Step-by-step explanation:

Given

$f(x)=3*5^{2x-3}$

Required

To determine if it is an exponential function, we have to write in form of

$f(x) = ab^x$

If we're able to do so, then the function is an exponential function.

If otherwise, then it is not

$f(x)=3*5^{2x-3}$

Apply Law of indices

$f(x)=3*\frac{5^{2x}}{5^3}$

Express 5^3 as 125

$f(x)=3*\frac{5^{2x}}{125}$

Factorize the exponent of 5

$f(x)=3*\frac{5^{(2)x}}{125}$

Express 5^2 as 25

$f(x)=3*\frac{25^x}{125}$

This can be rewritten as:

$f(x)=\frac{3}{125} * 25^x$

By comparing the above to $f(x) = ab^x$

We have that

$a = \frac{3}{125}$

$b^x = 25^x$

Since, we've be able to express the function as $f(x) = ab^x$

Then, $f(x)=3*5^{2x-3}$ is an exponential function

8 0

3 years ago

Suppose we want to choose 5 objects, without replacement, from 13 distinct objects. (a) How many ways can this be done, if the o

Arisa [49]

Answer:

A. 1, 287 ways

B. 154,440 ways

Step-by-step explanation:

A. We want to choose 5 objects from a total 13, without considering the order in which they are chosen.

The correct way to do this is by using the combination formula since order is not considered;

Thus we have ; 13 C 5 read as 13 combination 5;

Mathematically, n C r is ; n!/(n-r)!r!

Thus, we have ;

13!/(13-8)!8! = 13!/5!8! = 1,287 ways

B. By considering order, we shall be using the permutation formula;

Mathematically n P r = n!/(n-r)!

Read as n permutation r;

Using the numbers involved, we have ; 13 P 5

= 13!/(13-5)! = 13!/8! = 154,440 ways

8 0

3 years ago