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slavikrds [6]
3 years ago
8

Suppose we want to choose 5 objects, without replacement, from 13 distinct objects. (a) How many ways can this be done, if the o

rder of the choices is not taken into consideration? (b) How many ways can this be done, if the order of the choices is taken into consideration?
Mathematics
1 answer:
Arisa [49]3 years ago
8 0

Answer:

A. 1, 287 ways

B. 154,440 ways

Step-by-step explanation:

A. We want to choose 5 objects from a total 13, without considering the order in which they are chosen.

The correct way to do this is by using the combination formula since order is not considered;

Thus we have ; 13 C 5 read as 13 combination 5;

Mathematically, n C r is ; n!/(n-r)!r!

Thus, we have ;

13!/(13-8)!8! = 13!/5!8! = 1,287 ways

B. By considering order, we shall be using the permutation formula;

Mathematically n P r = n!/(n-r)!

Read as n permutation r;

Using the numbers involved, we have ; 13 P 5

= 13!/(13-5)! = 13!/8! = 154,440 ways

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Baby Amelia's parents measure her height every month.
jonny [76]

The statement H(30) = H(25) + 5 means that, "when Amelia was 30 months old, she was 5 centimeters taller than when she was 25 months old"

<h3><u>Solution:</u></h3>

Given that,

Baby Amelia's parents measure her height every month

It is given that H(t) models Amelia's height (in centimeters) when she was "t" months old

Given statement is H(30) = H(25) + 5

So, we can say that H(30) = Amelia's height when she was 30 months old

H(25) = Amelia's height when she was 25 months old

So H(30) = H(25) + 5 means that,

Height of Amelia when she was 30 months old is 5 centimeter more than Amelia height when she was 25 years old

Or we can say that,

When Amelia was 30 months old, she was 5 centimeters taller than when she was 25 months old

7 0
3 years ago
1/4 divides by 5/13=?
katrin2010 [14]
1/4 dividend by 5/13 is the same as
1/4 multiplied by 13/5 it’s inverse
1 x13 / 4x 5 = 13/20
8 0
3 years ago
Write an equation: the quotient of r and 258 is q
dedylja [7]
258 divided by r = q
4 0
3 years ago
Find the 97th term of the arithmetic sequence
kozerog [31]
<h2>Answer:</h2><h2>The 97th term in the series is 409</h2>

Step-by-step explanation:

The given sequence is 25, 29, 33, ....

The sequence represents arithmetic progression

In an AP, the first term is a1  = 25

The difference between two terms, d = 29 - 25 = 4

To find the 97th term,

By formula, a_{n}  = a_{1} + (n - 1) d

Substituting the values in the above equation, we get

a_{97}  = 25 + (97 - 1) 4

= 25 + (96 * 4)

= 25 + 384

= 409

The 97 th term in the given sequence is 409.

3 0
2 years ago
denny can deliver 6 papers every 15 minutes and brendan can deliver 5 papers in that same amount of time. how many papers can th
Evgesh-ka [11]

So for this problem you know that 15 is 1/4 of an hour so to get the amount of papers each individual could deliver by themselves in an hour you would multiply the amount they can deliver in 15 minutes by 4. Denny delivers 6 so multiplying that by 4 is 24. Next Brendan delivers 5 in 15 minutes so multiplying that by 4 you get 20. The final step is to add 20 and 24 to get the total amount of papers between the two of them that gets delivered in an hour. This will result in your answer of 44.

7 0
3 years ago
Read 2 more answers
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