What is the probability that you will get a 3-digit combination correct if no digits in the combination can be repeated?

2 answers:

7 0

If the digit of 0 is allowed, then:

1/(10*9*8)= 1/720

If it is not permitted, then:

1/(9*8*7)= 1/504

I hope this helps you!

Brainliest answer is always appreciated!

sergejj [24]3 years ago

7 0

Answer:

The probability that you will get a 3-digit combination correct is:

1/720

Step-by-step explanation:

We are asked to find the probability that you will get a 3-digit combination correct if no digits in the combination can be repeated.

Now the favorable number of outcomes=1 (which is the correct combination)

Total number of outcomes= 10×9×8

(first place has 10 choices of digits from 0-9 ,second has 9 choices excluding the one at first place and third place has 8 choice)

=720

Probability= number of favorable outcomes/total number of outcomes

= 1/720

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