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valina [46]
3 years ago
14

Pls help me my hw is due soon!!!!!!!

Mathematics
1 answer:
g100num [7]3 years ago
7 0
I think I can help, let me do some more existential research and I’ll get back to you
You might be interested in
(Crys) Im in 11 grade and in applied geometry I need help crys and how do you show
Snowcat [4.5K]

Answer:

1. -2/3        3. -5/4         5. 3/2          FOR THE REST OF THE PARTS LOOK THROUGH THE EXPLANATIONS

Step-by-step explanation:

Before I start the workings, I'll give a little explanation on this topic.

So, the equation of a straight line is

y = mx + c

where x and y are any coordinates of any point on the line.

m is the gradient or slope

m can be calculated using 2 formulas,

formula 1: Rise/Run

where rise is the how much a graph goes upwards or downwards, if its upwards use positive integer and if its downwards use negative integer.

Run is how much a graph moves to the right or to the left, if it moves to the right is is positive, if it moves to the left it is negative.

Formula 2: (y2-y1)/(x2-x1)

the values of these are taken through any 2 coordinates on the line.

and c is the y-intercept(the point where the line crosses the y-axis.

<u>MOVING TO ANSWERING NOW</u>

1. Dotted points on the line are (1,0) and (4,-2)

Formula of slope,

U can use any of the 2 formulas given above

I'll show both for this question

m = (y2-y1)/(x2-x1) = (-2-0)/(4-1) = -2/3

OR

m = rise/run = where rise is -2 and run is 3 so -2/3

2. TRY DOING THIS ONE YOURSELF

For the next part I'll do 3 and 5 for your understanding, try doing 2 and 4 on your own to understand.

3. Coordinates given (13,1) and (1,16)

m = (y2-y1)/(x2-x1) = (16-1)/(1-13) = 15/-12  simplify this and it becomes -5/4

5.  (-8,-14) and (-10,-17)

m =  (y2-y1)/(x2-x1) = (-17-(-14))/(-10-(-8)) = -3/-2 = 3/2

FOR THE NEXT PART I'LL DO 7,8 AND 10 FOR YOU, TRY DOING 9 ON YOUR OWN FOR PRACTICE.

I WILL ALSO ATTACH FILES FOR THE NEXT PARTS IN ORDER OF QUESTIONS SO SEE THEM.

7. y = x + 3 this means y = 1x +3 which means:

1 is the gradient

3 is the y-intercept

so 1 as a fraction is 1/1 which means rise is one upwards and run is 1 to the right.

Now go to the graph on the y-axis and plot the point 3, (0,3) is your y-intercept. From their rise by one and run by one this will lead u to point (1,4)

Mark both these points and make a line through them.

8. x = -5

now look at this equation in the form of y = mx + c

0 = 1x + 5 the means y is 0 and it is already told in the question that x = -5

if u rearrange 0 = 1x + 5 it will give you x = -5

now when y is  0 x = -5 put a point on the coordinate (-5,0) and draw a vertical straight line.

10. y = (1/4)x - 1

slope is 1/4 which means rise is 1 and run is 4

y-intercept is -1

now go to y=-1 which is the coordinate (0,-1) and rise by one and run by 4, this will take u to the coordinate (4,0) now put a dot on both coordinates, connect them and put a line through them.

3 0
2 years ago
HELP PLEASE NEED ANSWERS​
r-ruslan [8.4K]

Answer:

<u>Answer</u><u>:</u><u> </u><u>-</u><u>3</u><u>0</u>

Step-by-step explanation:

{(8 - 10)}^{2}  - 30 \div 5 \times 6 + 2

BODMAS

let's first solve the bracket:

=  {( - 2)}^{2}  - 30 \div 5 \times 6 + 2 \\  = 4 - 30 \div 5 \times 6 + 2

then let's divide:

= 4 - (30 \div 5) \times 6 + 2 \\  = 4 - 6 \times 6 + 2

then let's multiply:

= 4 - (6 \times 6) + 2 \\  = 4 - 36 + 2

simplify:

=  - 30

6 0
3 years ago
Help with the this question pleaseeee
34kurt

Answer:

32x - 8

Step-by-step explanation:

A = LW

A = (8x - 2)(4)

A = 32x - 8

7 0
3 years ago
Read 2 more answers
If 12g of a radioactive substance are present initially and 8yr later only 6g remain, how much if the substance will be present
Brums [2.3K]

The weight of substance remaining after 13 years is 2.25 g.

Given:

Present weight of substance = 12 g

After 8 years weight remains = 6 gm

Now, weight loss in 8 year will be,

12-6=6 gm

So, weight loss in 1 year will be,

\dfrac{6}{8} =\dfrac{3}{4}

Total weight loss in 13 year will be,

\dfrac{3}{4}\times13=9.75

The weight of substance remaining after 13 years will be,

12- 9.75 = 2.25 \;\rm g

Therefore, the weight of substance remaining after 13 years is 2.25 g.

To know more about radioactive decay, refer to the link:

brainly.com/question/12116123

5 0
3 years ago
ABC is a triangle. ACD is an isosceles triangle. Find ACB and ABC.
GREYUIT [131]

Answer:

∠ ACB = 128° and ∠ABC = 32°

Step-by-step explanation:

∠ ADC = ∠ CAD (base angles theorem)

∠ ACD = 82° (angles in a triangle add to 180°)

∠ ACB = 128° (angles around a point add to 360°)

∠ ABC = 32° (angles in a triangle add to 180°)

7 0
2 years ago
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