Ask question

Ask question

All categories

3 years ago

5

Can someone please help me?

1 answer:

luda_lava [24]3 years ago

5 0

$\bf t=165x+2771\qquad 
\begin{cases}
x=\textit{years since 1996}\\
t=\textit{tuition average fees}\\
----------\\
t=5576
\end{cases}
\\\\\\
5576=165x+2771\implies 5576-2771=165x\implies 2805=165x
\\\\\\
\cfrac{2805}{165}=x\implies \boxed{17=x}\\\\
-----------------------------\\\\
1996+\boxed{17}\implies 2013$

You might be interested in

The point 3,2 reflected in the x-axis is

Serga [27]

(3.-2)

HOPE THIS WILL HELP U

5 0

3 years ago

Read 2 more answers

What is the answer to 10 to the power of 8

antoniya [11.8K]

Answer:

Step-by-step explanation:

10^8

it means multiply 10 8 times so

10*10*10*10*10*10*10*10

=100000000

5 0

3 years ago

Which expression is a cube root of -1+i√3?

Tpy6a [65]

Answer:

<em>The correct option is C.</em>

Step-by-step explanation:

<u>Root Of Complex Numbers</u>

If a complex number is expressed in polar form as

$Z=(r,\theta)$

Then the cubic roots of Z are

$\displaystyle Z_1=\left(\sqrt[3]{r},\frac{\theta}{3}\right)$

$\displaystyle Z_2=\left(\sqrt[3]{r},\frac{\theta}{3}+120^o\right)$

$\displaystyle Z_3=\left(\sqrt[3]{r},\frac{\theta}{3}+240^o\right)$

We are given the complex number in rectangular components

$Z=-1+i\sqrt{3}$

Converting to polar form

$r=\sqrt{(-1)^2+(\sqrt{3})^2}=2$

$\displaystyle tan\theta=\frac{\sqrt{3}}{-1}=-\sqrt{3}$

It's located in the second quadrant, so

$\theta=120^o$

The number if polar form is

$Z=(2,120^o)$

Its cubic roots are

$\displaystyle Z_1=\left(\sqrt[3]{2},\frac{120^o}{3}\right)=\left(\sqrt[3]{2},40^o\right)$

$\displaystyle Z_2=\left(\sqrt[3]{2},40^o+120^o\right)=\left(\sqrt[3]{2},160^o\right)$

$\displaystyle Z_3=\left(\sqrt[3]{2},40^o+240^o\right)=\left(\sqrt[3]{2},280^o\right)$

Converting the first solution to rectangular coordinates

$z_1=\sqrt[3]{2}(\ cos40^o+i\ sin40^o)$

The correct option is C.

8 0

3 years ago

Andrew lives at an altitude of 135 feet, and his friend Lisa lives at an altitude of -10 feet.

Talja [164]

Answer:

Andrew's residence is higher

3 0

3 years ago

31) Joe spent half of his weekly allowance

julia-pushkina [17]

To help solve this problem, create a simple equation.

Let x = weekly allowance.

(x/2) + $4 = $11. Subtract 4 from each side

(x/2) = 7. Multiply each side by 2

x = $14.

Joe's weekly allowance is $14

7 0

4 years ago

Read 2 more answers