I need help on what to do for part b

How does using visual models help us understand dividing fractions by whole numbers?

aleksley [76]

My friend have the same problem can you let me know when you find out ? I

3 0

3 years ago

Find the equation of a line that goes through the points (8, -9) and (-4, 15).

Natasha_Volkova [10]

Answer:

y = - 2x + 7

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (8, - 9) and (x₂, y₂ ) = (- 4, 15)

m = $\frac{15+9}{-4-8}$ = $\frac{24}{-12}$ = - 2, thus

y = - 2x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (8, - 9), then

- 9 = - 16 + c ⇒ c = - 9 + 16 = 7

y = - 2x + 7 ← equation of line

3 0

3 years ago

An urn contains 5 white and 10 black balls. A fair die is rolled and that number of balls is randomly chosen from the urn. What

galina1969 [7]

Answer:

Part A:

The probability that all of the balls selected are white:

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

$P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

Step-by-step explanation:

A is the event all balls are white.

D_i is the dice outcome.

Sine the die is fair:

$P(D_i)=\frac{1}{6}$ for i∈{1,2,3,4,5,6}

In case of 10 black and 5 white balls:

$P(A|D_1)=\frac{5_{C}_1}{15_{C}_1} =\frac{5}{15}=\frac{1}{3}$

$P(A|D_2)=\frac{5_{C}_2}{15_{C}_2} =\frac{10}{105}=\frac{2}{21}$

$P(A|D_3)=\frac{5_{C}_3}{15_{C}_3} =\frac{10}{455}=\frac{2}{91}$

$P(A|D_4)=\frac{5_{C}_4}{15_{C}_4} =\frac{5}{1365}=\frac{1}{273}$

$P(A|D_5)=\frac{5_{C}_5}{15_{C}_5} =\frac{1}{3003}=\frac{1}{3003}$

$P(A|D_6)=\frac{5_{C}_6}{15_{C}_6} =0$

Part A:

The probability that all of the balls selected are white:

$P(A)=\sum^6_{i=1} P(A|D_i)P(D_i)$

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

We have to find $P(D_3|A)$

The data required is calculated above:

$P(D_3|A)=\frac{P(A|D_3)P(D_3)}{P(A)}\\ P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

7 0

3 years ago

Find the measure of 46. 70*110° 46 o 66 = [?]

IgorLugansk [536]

Angle 6 is 110 degrees

5 0

3 years ago

Read 2 more answers

An isosceles triangle has two sides of equal length, a, and a base, b. The perimeter of the triangle is 15.7 inches, so the equa

Setler [38]

Answer:

b=0.5 in

b=2 in

Step-by-step explanation:

we know that

The perimeter of triangle is equal to

$2a+b=15$

Solve for a

$a=\frac{15-b}{2}$ -----> equation A

Applying the Triangle Inequality Theorem

a+a > b

2a > b -----> inequality B

Verify each case

case 1) b=-2 in

This value not make sense, the length side cannot be a negative number

case 2) b=0 in

This value not make sense

case 3) b=0.5 in

substitute the value of b in the equation A and solve for a

$a=\frac{15-0.5}{2}=7.25\ in$

substitute the values of b and a in the inequality B

2a > b

2(7.25) > 0.5

14.50 > 0.5 -----> is true

therefore

b=0.5 in make sense for possible values of b

case 4) b=2 in

substitute the value of b in the equation A and solve for a

$a=\frac{15-2}{2}=6.5\ in$

substitute the values of b and a in the inequality B

2a > b

2(6.5) > 2

13 > 2 -----> is true

therefore

b=2 in make sense for possible values of b

case 5) b=7.9 in

substitute the value of b in the equation A and solve for a

$a=\frac{15-7.9}{2}=3.55\ in$

substitute the values of b and a in the inequality B

2a > b

2(3.55) >7.9

7.1 > 7.9 -----> is not true

therefore

b=7.9 in not make sense for possible values of b

5 0

3 years ago

Read 2 more answers