Answer:1. They make policies
2. They perform executive duties
3. They plan environmental and land use policy
Step-by-step explanation:
Answer:
14.63% probability that a student scores between 82 and 90
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 72.3, \sigma = 8.9](https://tex.z-dn.net/?f=%5Cmu%20%3D%2072.3%2C%20%5Csigma%20%3D%208.9)
What is the probability that a student scores between 82 and 90?
This is the pvalue of Z when X = 90 subtracted by the pvalue of Z when X = 82. So
X = 90
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{90 - 73.9}{8.9}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B90%20-%2073.9%7D%7B8.9%7D)
![Z = 1.81](https://tex.z-dn.net/?f=Z%20%3D%201.81)
has a pvalue of 0.9649
X = 82
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{82 - 73.9}{8.9}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B82%20-%2073.9%7D%7B8.9%7D)
![Z = 0.91](https://tex.z-dn.net/?f=Z%20%3D%200.91)
has a pvalue of 0.8186
0.9649 - 0.8186 = 0.1463
14.63% probability that a student scores between 82 and 90
Answer:
-2
Step-by-step explanation:
Answer:
5.5 gallons
Step-by-step explanation:
There are 4 quarts in 1 gallon.
22 ÷ 4 = 5.5
I hope this helps :)