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3 years ago

After losing the __________, the Chinese government was forced to make reparation payments to Britain.

Mathematics

2 answers:

Julli [10]3 years ago

7 0

Answer: a.anglo-chinese war in e2020

Step-by-step explanation:

SVEN [57.7K]3 years ago

4 0

Option A. Anglo-Chinese War.

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Please answer number 29 ASAP

Effectus [21]

$h = 5b - 2$

$\frac 1 2 b h= 36$

$b(5b - 2) = 72$

$5b^2 - 2b - 72 = 0$

$(b - 4)(5b + 18) = 0$

$b = 4 \textrm{ or }b = -18/5$

We can rule out the negative length.

$h = 72/b = 72/4 = 18$

Answer: b=4, h=18

3 0

3 years ago

Read 2 more answers

Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

finlep [7]

Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

b) $a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

c) $\int v dt = s(t) = [L]=L$

d) $\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

e) $\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

7 0

3 years ago

is vector v with an initial point of (-5,22) and a terminal point of (20,60) equal to vector u with an intintal point of (50,120

marta [7]

Answer:

Yes, vectors u and v are equal.

Step-by-step explanation:

We need to check whether vectors u and v are equal or not.

If the initial point is $(x_1,y_1)$ and terminal point is $(x_2,y_2)$ , then the vector is

$Vector=(x_2-x_1)i+(y_2-y_1)j$

Vector v with an initial point of (-5,22) and a terminal point of (20,60).

$\overrightarrow v=(20-(-5))i+(60-22)j$

$\overrightarrow v=25i+38j$ ..... (1)

Vector u with an initial point of (50,120) and a terminal point of (75,158).

$\overrightarrow u=(75-50)i+(158-120)j$

$\overrightarrow u=25i+38j$ .... (2)

From (1) and (2) we get

$\overrightarrow u=\overrightarrow v$

Therefore, vectors u and v are equal.

5 0

3 years ago

Problem 2

Nezavi [6.7K]

Answer:

$109.27

Step-by-step explanation:

100 + 90 = 190

54/100 X 190 = 102.60

100 + 6.5 = 106.5

102.60/100 X 106.5 = 109.269

monetary unit round to 2dp

109.27

4 0

2 years ago

I need help Real quick! ASAP, One/Two Step Equation Word Problems | Define the Variables for each problem.

faltersainse [42]

Answer:

6) Braden scored 77.

7) Carolyn bought 18 pocket folders.

Step-by-step explanation:

6) 86 - 9 = 77

7) 0.39x = 7.02

step 1- divide both sides by 0.39

x = 18

3 0

3 years ago

Read 2 more answers