Is this a function or not a function

If 3 kg of flour needs 4 1/2 cups of sugar how much is 4 kg Of flour

den301095 [7]

Answer:

This is the formula of how to answer this question hopefully it helps :)

Sugar = Flour

A cup of sugar weighs about 7 ounces, and a cup of all-purpose flour weighs about 4-1/2 ounces. So, if we're building a recipe with 1 cup sugar, we'll need about 1-1/2 cups flour (about 6-3/4 ounces).

Step-by-step explanation:

6 0

4 years ago

the ratio of the masses of flour in two bags is 5 : 7 the heaver bag contains 1,120 grams of flour. What is the total masses of

Vladimir79 [104]

1120:7=160. 160(5)=800. 1120+800=1920

3 0

3 years ago

Solve the equation for x

Ahat [919]

Answer:

B. x = -4

Step-by-step explanation:

- 7x - 35 = -7

add 35 to both sides

-7x = 28

Divde both sides by -7

x = -4

6 0

3 years ago

Read 2 more answers

Find the standard equation of a sphere that has diameter with the end points given below. (3,-2,4) (7,12,4)

DiKsa [7]

Answer:

The standard equation of the sphere is $(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

Step-by-step explanation:

From the question, the end point are (3,-2,4) and (7,12,4)

Since we know the end points of the diameter, we can determine the center (midpoint of the two end points) of the sphere.

The midpoint can be calculated thus

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Let the first endpoint be represented as $(x_{1}, y_{1}, z_{1})$ and the second endpoint be $(x_{2}, y_{2}, z_{2})$ .

Hence,

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Midpoint = $(\frac{3 + 7 }{2}, \frac{-2+12 }{2}, \frac{4 + 4 }{2})$

Midpoint = $(\frac{10 }{2}, \frac{10}{2}, \frac{8 }{2})\\$

Midpoint = $(5, 5, 4)$

This is the center of the sphere.

Now, we will determine the distance (diameter) of the sphere

The distance is given by

$d = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2} + (z_{2}- z_{1})^{2} }$

$d = \sqrt{(7 - 3)^{2} +(12 - -2)^{2} + (4- 4)^{2}$

$d = \sqrt{(4)^{2} +(14)^{2} + (0)^{2}$

$d = \sqrt{16 +196 + 0$

$d =\sqrt{212}$

$d = 2\sqrt{53}$

This is the diameter

To find the radius, r

From $Radius = \frac{Diameter}{2}$

$Radius = \frac{2\sqrt{53} }{2}$

∴ $Radius = \sqrt{53}$

r = $\sqrt{53}$

Now, we can write the standard equation of the sphere since we know the center and the radius

Center of the sphere is $(5, 5, 4)$

Radius of the sphere is $\sqrt{53}$

The equation of a sphere of radius r and center $(h,k,l)$ is given by

$(x-h)^{2} + (y-k)^{2} + (z-l)^{2} = r^{2}$

Hence, the equation of the sphere of radius $\sqrt{53}$ and center $(5, 5, 4)$ is

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = \sqrt{(53} )^{2}$

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

This is the standard equation of the sphere

6 0

3 years ago

Shaquana is playing a board game. The probability that Shaquana will lose a turn on

Colt1911 [192]

Answer:

Unlikely

Step-by-step explanation:

50/50 means that there is half a chance to loose a turn or 6/12 which is not the case.

Certain is definitely not correct as there is only 1/12 of a chance.

And impossible is not possible because it would have to be 0/12. There is still a chance to loose a turn with 1/12

7 0

3 years ago