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4 years ago

Explain whether the function g(x) = x^9 + x^5 is borh an even function and an odd function.

Mathematics

1 answer:

Ilia_Sergeevich [38]4 years ago

5 0

Answer:

The answer is B

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The GCF of 18 and 27 is _______.

Gnoma [55]

Answer:

Step-by-step explanation:

The factors of 18 are : 1, 2, 3, 6, 9, 18

The factors of 27 are : 1, 3, 9, 27

The common factors are : 1, 3, 9

The gcf is 9

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3 years ago

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iris [78.8K]

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7 lenth

Step-by-step explanation:

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3 years ago

HELP ASAP!!!!! find the value of x. a. 16 b. 18 c. 12 d. 28

Anit [1.1K]

I think C.12

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3 years ago

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A spherical balloon currently has a radius of 19cm. If the radius is still growing at a rate of 5cm or minute, at what rate is a

miv72 [106K]

Answer:

22670.8 cm³/min

Step-by-step explanation:

Given:

Radius of the balloon at a certain time (r) = 19 cm

Rate of growth of radius is, $\frac{dr}{dt}=5\ cm/min$

The rate at which the air is pumped in the balloon can be calculated by finding the rate of increase in the volume of the balloon.

So, first we find the volume of the sphere in terms of 'r'. As the balloon is spherical in shape, the volume of the balloon is equal to the volume of a sphere. Therefore,

Volume of balloon is given as:

$V=\frac{4}{3}\pi r^3$

Now, rate of increase of volume is obtained by differentiating both sides of the equation with respect to time 't'.

Differentiating both sides with respect to time 't', we get:

$\frac{dV}{dt}=\frac{d}{dt}(\frac{4}{3}\pi r^3)\\\\\frac{dV}{dt}=\frac{4\pi}{3}(3r^2)(\frac{dr}{dt})\\\\\frac{dV}{dt}=4\pi r^2(\frac{dr}{dt})$

Now, plug in 19 cm for 'r', 5 cm per minute for $\frac{dr}{dt}$ and solve for $\frac{dV}{dt}$ . This gives,

$\frac{dV}{dt}=4\pi (19 cm)^2(5\ cm/min)\\\\\frac{dV}{dt}=4\times 3.14\times 361\times 5\ cm^3/min\\\\\frac{dV}{dt}=22670.8\ cm^3/min$

Therefore, the rate at which the air is being pumped into the balloon is 22670.8 cm³/min.

4 0

4 years ago

Area of a parallelagram

Ludmilka [50]

Area=base and height

7 0

3 years ago