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3 years ago

Given the function p below, which statement correctly compares the values of p(1) and p(2)? P(x)=4 x

Mathematics

1 answer:

oksano4ka [1.4K]3 years ago

7 0

Answer:

The value of P(2) is twice that of P(1).

Step-by-step explanation:

P(x) = 4x so:

P(1) = 4*1 = 4 and

P(2) = 4*2 = 8.

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82 less than r is less than -164

Oliga [24]

Answer:

82<r<-164

Step-by-step explanation:

We need to form an inequality of the given statement.

82 less than r is less than -164

Less than is written as <.

82 less than r means, 82<r

r is less than -164, r<-164

Combining two statements,

82<r<-164

Hence, the expression for 82 less than r is less than -164 is 82<r<-164.

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3 years ago

Is there a difference between arcsin and inverse sine?

Anna007 [38]

I hope this helps you

f(x) =sinx

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3 years ago

G (r) = 25 – 3r<br> g(4) =

tensa zangetsu [6.8K]

Answer:

=25 - 3 × 4

= 25-12= 13

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8 0

3 years ago

Read 2 more answers

Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

7 0

3 years ago

Can you guys answer this ?

nika2105 [10]

Answer:

-7

...................

7 0

3 years ago

Read 2 more answers