Given in triangle ABC segment DE is parallel to the side AC . (The endpoints of segment DE lie on the sides AB and BC respectively). we have to find the length of DE.

Given lengths are AC=20cm, AB=17cm, and BD=11.9cm

In ΔBDE and ΔBAC

∠BDE=∠BAC (∵Corresponding angles)

∠BED=∠BCA (∵Corresponding angles)

By AA similarity rule, ΔBDE~ΔBAC

∴their corresponding sides are in proportion

⇒ $\frac{BE}{BC}=\frac{BD}{BA}=\frac{DE}{AC}$

⇒ $\frac{BD}{BA}=\frac{DE}{AC}$

⇒ $\frac{11.9}{17}=\frac{DE}{20}$

⇒ $DE=\frac{20\times 11.9}{17}=14cm$

5 0

3 years ago

Find the zeros of the function f(x)=-0.3x^2+0.6x+3.8 to the nearest hundredth

Paul [167]

Ce clasă ești sa văd daca te pot ajuta

6 0

3 years ago

What is the Constant in <br> 3x + 7

lys-0071 [83]

7 because the 3 is the coefficient and the x is the variable. The + is the operator so that leaves you the 7

4 0

3 years ago

8x6+(12-4)/2 equal what is sum???

algol13

$8 \times 6 + \dfrac{(12-4)}{2}$

$=48+ \dfrac{8}{2}$

$=48 + 4$

$=52$

8 0

3 years ago

Read 2 more answers