All categories

3 years ago

How do u write 19/25 fraction or mixed number as a decimal

Mathematics

2 answers:

Romashka [77]3 years ago

8 0

Divide the bottom into the top for a decimal

Colt1911 [192]3 years ago

8 0

To get 19/25 as a decimal, divide 19 by 25 (19 ÷ 25) and get 0.76.

You might be interested in

Pls can someone tell me what sine is

QveST [7]

Answer:

the trigonometric function that is equal to the ratio of the side opposite a given angle (in a right triangle) to the hypotenuse.

Step-by-step explanation:

5 0

2 years ago

Scientists specializing in nutrition conduct studies that provide us with the information we need to make healthy

saul85 [17]

Answer:

1. The greatest overall benefits appear in people who drink (2-3 )cups of coffee per day.

2. Why is it difficult to say for sure whether coffee has a good enect on the body ( lifestyle choices associated with coffee consumption also impact health).

3. Which of these is not a benefit associated with contee consumption ( lower chance of migraines.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A polygon is broken up into 5 non-overlapping triangles by drawing lines from one vertex to all other non-adjacent vertices. Wha

pshichka [43]

C. Heptagon

Just took the test on edgen.....

5 0

2 years ago

Read 2 more answers

What is the slope of the line whose equation is

svetlana [45]

Answer:

-3

Step-by-step explanation:

Because it is multiplied by x

7 0

2 years ago

Read 2 more answers

An equation of an ellipse is given. y2 = 1 − 3x2 (a) Find the vertices, foci, and eccentricity of the ellipse. vertex (x, y) = (

oksian1 [2.3K]

Answer:

Step-by-step explanation:

Given

$y^2=1-3x^2$

$3x^2+y^2=1$

$\frac{x^2}{(\frac{1}{\sqrt{3}})^2}+\frac{y^2}{1}=1$

therefore it is a vertical ellipse

thus a=1

$b=\frac{1}{\sqrt{3}}$

eccentricity of Ellipse

$e^2=1-\frac{b^2}{a^2}$

$e^2=1-\frac{1}{(\sqrt{3})^2}$

$e^2=1-\frac{1}{3}$

$e^2=\frac{2}{3}$

$e=\sqrt{\frac{2}{3}}$

Focii are $(0,ae)$ and $(0,-ae)$

$ae=1\times \sqrt{\frac{2}{3}}$

thus focii are $(0,\sqrt{\frac{2}{3}})$ & $(0,-\sqrt{\frac{2}{3}})$

(b) Length of major axis $=2a=2\times 1$

length of minor axis $=2b=2\times \sqrt{\frac{2}{3}}=2\cdot \sqrt{\frac{2}{3}}$

8 0

2 years ago