The figure below shows a triangular wooden frame ABC. The side AD of the frame has rotted and needs to be replaced:

I really need help !!

Mekhanik [1.2K]

Answer:

A. 24 in

Step-by-step explanation:

Because side GF was multiplied by 4, the rest can be calculated in that same manner.

3 0

2 years ago

Read 2 more answers

ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions

aliina [53]

Answer: B. H(t) = -6.9(t - 2.3)² + 112

Step-by-step explanation:

The vertex form of a quadratic equation is: y = a(x - h)² + k

where (h, k) is the vertex ⇒ k is the maximum height

the distance traveled is when y = 0 ⇒ $x=\sqrt{\dfrac{-k}{a}}+h$

Given: H(t) = -7.1(t - 2.3)² + 98

maximum height (k) = 98 feet

distance traveled (x) = $\sqrt{\dfrac{-98}{-7.1}}+2.3$ = 6.02 seconds

A) H(t) = -7.5(t - 2.2)² + 112

maximum height (k) = 112 feet

distance traveled (x) = $\sqrt{\dfrac{-112}{-7.5}}+2.2$ = 6.06 seconds

B) H(t) = -6.9(t - 2.3)² + 112

maximum height (k) = 112 feet

distance traveled (x) = $\sqrt{\dfrac{-112}{-6.9}}+2.3$ = 6.33 seconds

C) H(t) = -6.9(t - 2.4)² + 95

maximum height (k) = 95 feet

This has a lower height than the given equation.

D) H(t) = -7.5(t - 2.3)² + 95

maximum height (k) = 95 feet

This has a lower height than the given equation.

Both options A and B travel higher and stay in the air longer than last year's winner, however option B stays in the air longer than option A.

5 0

3 years ago

Suppose it is known that 60% of radio listeners at a particular college are smokers. A sample of 500 students from the college i

vladimir1956 [14]

Answer:

The probability that at least 280 of these students are smokers is 0.9664.

Step-by-step explanation:

Let the random variable X be defined as the number of students at a particular college who are smokers

The random variable X follows a Binomial distribution with parameters n = 500 and p = 0.60.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1. np ≥ 10

2. n(1 - p) ≥ 10

Check the conditions as follows:

$np=500\times 0.60=300>10\\n(1-p)=500\times(1-0.60)=200>10$

Thus, a Normal approximation to binomial can be applied.

So,

$X\sim N(\mu=600, \sigma=\sqrt{120})$

Compute the probability that at least 280 of these students are smokers as follows:

Apply continuity correction:

P (X ≥ 280) = P (X > 280 + 0.50)

= P (X > 280.50)

$=P(\frac{X-\mu}{\sigma}>\frac{280-300}{\sqrt{120}}\\=P(Z>-1.83)\\=P(Z$

*Use a z-table for the probability.

Thus, the probability that at least 280 of these students are smokers is 0.9664.

8 0

3 years ago

Evaluate each expression for the given values of the variables.

antiseptic1488 [7]

All of these involve simple substitution. Just replace the variable with the actual value.

8z + 3 >>> 8(8) + 3 = 64 + 3 = 67

3(7+ x^2) >>> 3(7 + 2^2) = 3(7 + 4) = 3(11)=33

s - 5t + s^2 >>> 4 - 5(-1) + 4^2 = 4 + 5 + 16

Get the trend? I am not sure I get that last one, is it:

x - y*3^2?

8 0

4 years ago

Please help me if you can. Please also write how you got the answer thank you.

adelina 88 [10]

Answer:

1) r, q, s. 2). 5

Step-by-step explanation:

1) from the given (q) is smaller than (r) and (s) is less than (q) by 2.

2) you need to make all the fractions have the same numerator so you will multiply both the firs and third fraction by 3÷3 ( which is 1 and will not affect the value but will make the numerator of the fractions equal) and the fractions between them is the second fraction and it's denominator is x and there is 5 fractions between the two numbers so there are 5 possible values of x

6 0

3 years ago