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Ivenika [448]
3 years ago
10

9. The sum of two consecutive integers is 41 less than four times the larger. Find the numbers.

Mathematics
1 answer:
Maksim231197 [3]3 years ago
5 0

Answer:

19 and 20

Step-by-step explanation:

Let x be the larger number

x - 1 + x = 4x - 41

We can combine like terms and isolate x:

2x - 1 = 4x - 41

2x = 40

x = 20

20 - 1 = 19

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Let ℤ17 be the ring of integers modulo 17, and let ℤ×17 be the group of units of ℤ17 under multiplication. Which of the followin
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Answer:  The correct option is (E) I, II and III.

Step-by-step explanation:  Given that ℤ17 be the ring of integers modulo 17, and let ℤ×17 be the group of units of ℤ17 under multiplication.

We are to select the correct generators of ℤ×17.

According to the given information, we can write

ℤ17 = {0, 1, 2, 3, . . . , 16}

and

ℤ×17 = {1, 2 , 3 , . . . 16}.

The generators of ℤ×17 are those elements which are co prime to 17.

Since all the elements from 1 to 16 are co prime to 17, so all the elements of the set  ℤ×17 are its generators.

Therefore, 5, 8 and 16, all are generators. So, i, ii and iii are generators.

Thus, (E) is the correct option.

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3 years ago
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I need help
mihalych1998 [28]

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