2 years ago

9. The sum of two consecutive integers is 41 less than four times the larger. Find the numbers.

1 answer:

5 0

Answer:

19 and 20

Step-by-step explanation:

Let x be the larger number

x - 1 + x = 4x - 41

We can combine like terms and isolate x:

2x - 1 = 4x - 41

2x = 40

x = 20

20 - 1 = 19

You might be interested in

andrew-mc [135]

X=3 , -3

Shsjdhshajbahe

5 0

3 years ago

Alekssandra [29.7K]

Answer:

A. -12h² - 22h + 14

Step-by-step explanation:

(-4h +2)(3h +7) = -4h(3h +7) +2(3h +7) . . . . . . . (a +b)c = ac +bc

= (-4h)(3h) + (-4h)(7) + (2)(3h) + (2)(7) . . . . . . . a(b +c) = ab +ac . . . (twice)

= -12h² -28h +6h +14

= -12h² -22h +14 . . . . . . . . collect terms

3 0

3 years ago

satela [25.4K]

I cant really see the words

3 0

3 years ago

IrinaVladis [17]

$y = 6$
the equation is the horizontal line which parts through (-5,6), since it has no slope.

3 0

3 years ago

Vilka [71]

Z = (10.1 - 7.7) / 2.5 = 2.4 / 2.5 = 0.96

6 0

2 years ago