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3 years ago

What is the equation of the line that passes through the point (5, 4) and has a slope of 4/5

Mathematics

1 answer:

nataly862011 [7]3 years ago

8 0

Answer:

Every point on a horizontal line has the same y-value. Use the y-value of the point to find the equation of the horizontal line.

y=4

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PLS HELP WHAT ARE THESE TWO ILL GIVE BRAINLESS AND SHOW UR WORK

Hitman42 [59]

Answer:

2) C

3) 62 degrees

Step-by-step explanation:

72+46=118

180-118

Hope this helps

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2 years ago

4 x (-4) dived by (2) - (-3) + (-6)

spayn [35]

Answer: the answer that i got was -11

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2 years ago

(9x−2.25)=(1.6+9x)<br><br> help

mel-nik [20]

Begin solving like you normally would. Add 2.25 to both sides and subtract 9x from both sides to try getting all x values on one side. However, you will find that after subtracting 9x from both sides, all x values go away, and you end with -2.25=1.6. This is not true (-2.25 is not 1.6), so the answer is no solution. There is no value of x which satisfies that equation.

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3 years ago

Scores are 78,81,83, and 76 what must she earn on the fifth test to earn an average test score of 81

iogann1982 [59]

The average value of a data set is equal to the sum of each entry divided by the number of entries. In this case, we have 5 scores, so we can find set up the following equation where x is the fifth score:

$\dfrac{78+81+83+76+x}{5} = 81$

Now solve for x:

$78 + 81 + 83 + 76 + x = 81(5)$

$318 + x = 405$

$x = 87$

The fifth score must be 87.

6 0

2 years ago

Read 2 more answers

Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.

adoni [48]

Answer: The required derivative is $\dfrac{8x^2+18x+9}{x(2x+3)^2}$

Step-by-step explanation:

Since we have given that

$y=\ln[x(2x+3)^2]$

Differentiating log function w.r.t. x, we get that

$\dfrac{dy}{dx}=\dfrac{1}{[x(2x+3)^2]}\times [x'(2x+3)^2+(2x+3)^2'x]\\\\\dfrac{dy}{dx}=\dfrac{1}{[x(2x+3)^2]}\times [(2x+3)^2+2x(2x+3)]\\\\\dfrac{dy}{dx}=\dfrac{4x^2+9+12x+4x^2+6x}{x(2x+3)^2}\\\\\dfrac{dy}{dx}=\dfrac{8x^2+18x+9}{x(2x+3)^2}$

Hence, the required derivative is $\dfrac{8x^2+18x+9}{x(2x+3)^2}$

3 0

3 years ago