Answer:
-8a(a+3b)
Step-by-step explanation:
(2a+6b)(6b−2a)−(2a+6b)^2
(2a+6b) {(6b−2a)−(2a+6b)(2a+6b)}
2(a+3b) (6b-2a-2a-6b)
2(a+3b) (-4a)
-2(a+3b) x 4a
-2 x 4a (a+3b)
-8a(a+3b)
Given that Trent's watch runs at half the speed it should run, this implies that
for every hour passed, his watch moves by half an hour.
Hence, for every half-hour passed, Trent's watch moves by 15 minutes.
Hence, when the real time is 10:30 am, Trent's watch will show 9:15 am.
1, ___, ____, _____, _____, _____, ____, 29
29-1 = 28
28/7 = 4
1, 5, 9, 13, 17, 21, 25, 29
Answer:

Step-by-step explanation:
V=Tr^2h
V / T = r^2 h
V / Th = r^2
√V / Th

D/H = 0.25
18/H = 0.25/1
Cross multiply and solve for H