Answer:
5/3
Step-by-step explanation:
to find the slope, we have to use the formula y2-y1 over x2-x1. Now, plug in our values; 8-28 over 6-18. Our answer becomes -20 over -12 this simplifies to 5 over 3, and there's your answer.
In order to figure out whether Luis or Isabella skates farther to get to school, we have to create a common denominator between the two fractions that represent the distance that each person walks.
The least common denominator of 3 and 4 is 12. This means that we have to change both fractions into equal fractions with denominators of 12.
To figure this out, we must set up a proportion.
2/3 = x/12
To solve this proportion, we must cross-multiply the fractions. We get:
24 = 3x
If we divide both sides by the coefficient of x which is 3, to get the variable x alone, we get:
x = 8
Therefore, 2/3 = 8/12, so Luis skates 8/12 mile from his home to school.
If we do the same process for the 2/4 mile to get to school for Isabella, we get 6/12, because both fractions are equal to 1/2.
Therefore, we know that Luis skates 8/12 mile to school and Isabella skates 6/12 mile to get to school. Because they have the same denominator, we can just compare the numerators. We know that 8 is greater than 6, thus Luis skates farther to get to school.
Answer:
10 and 12
Step-by-step explanation:
let the consecutive even integers be n and n + 2 , then
n² - 64 = 3(n + 2) ← distribute parenthesis
n² - 64 = 3n + 6 ( subtract 3n + 6 from both sides )
n² - 3n - 70 = 0 ← in standard form
(n - 10)(n + 7) = 0 ← in factored form
Equate each factor to zero and solve for n
n - 10 = 0 ⇒ n = 10
n + 7 = 0 ⇒ n = - 7
Since n must be a positive even integer then n = 10 and n + 2 = 10 + 2 = 12
The 2 numbers are 10 and 12
<span>The median would be preferred over the mean in such scenarios because the median will lessen the impact of the outliers that fall within the "tail" of the skew. Therefore, if a curve is normally distributed, that is to say that data is normally distributed, there will be two tails, each with approximately equal proportions of outliers. Outliers in this case being more extreme numbers, and are based on your determination depending on how you are using the data. If data is skewed there is one tail, and therefore it may be an inaccurate measure of central tendency if you use the mean of the numbers. Thinking of this visually. In positively skewed data where there is a "tail" towards the right and a "peak" towards the left, the median will be placed more in the "peak", whereas the mean will be placed more towards the "tail", making it a poorer measure of central tendency, or the center of the data.</span>