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3 years ago

What 3 ratios that are equivalent

Mathematics

2 answers:

Arturiano [62]3 years ago

7 0

Answer:1:3

2:6

4:12

Step-by-step explanation:

steposvetlana [31]3 years ago

4 0

Answer:

1:2, 2:4, 3:6

Step-by-step explanation:

If you times 1:2 by 2, you get 2:4. If you times 1:2 by 3, you get 3:6.

You have to multiply each individual number in the ratio.

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Use the graph of the function to find the domain of f. (Enter your answer using interval notation.).

Ulleksa [173]

Answer:

Domain: (-∞,0) ∪ [0,∞)

Range: [-3,∞)

f(0) = -3

6 0

3 years ago

The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature

Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

$T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$

Where

$(t) = \ time$

$T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)$

$T_{s} = Surrounding \ temperature$

$T_{0} = Initial \ temperature \ of \ the \ body$

$k = constant$

From the question,

$T_{0} = 86 ^{o}C$

$T_{s} = -20 ^{o}C$

∴ $T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C$

$T_{0} - T_{s} = 106^{o} C$

Therefore, the equation $T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$ becomes

$T_{(t)}=-20+106 e^{kt}$

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time $t = 1 \ hour$ , $T_{(t)} = 58^{o}C$

Then, we can write that

$T_{(1)}=58 = -20+106 e^{k(1)}$

Then, we get

$58 = -20+106 e^{k(1)}$

Now, solve for $k$

First collect like terms

$58 +20 = 106 e^{k}$

$78 =106 e^{k}$

Then,

$e^{k} = \frac{78}{106}$

$e^{k} = 0.735849$

Now, take the natural log of both sides

$ln(e^{k}) =ln( 0.735849)$

$k = -0.30673$

This is the value of the constant $k$

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at $t = 2 \ hours$

From

$T_{(t)}=-20+106 e^{kt}$

Then

$T_{(2)}=-20+106 e^{(-0.30673 \times 2)}$

$T_{(2)}=-20+106 e^{-0.61346}$

$T_{(2)}=-20+106\times 0.5414741237$

$T_{(2)}=-20+57.396257$

$T_{(2)}=37.396257 \ ^{o}C$

$T_{(2)} \approxeq 37.40 \ ^{o}C$

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

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2 years ago

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A computer repairman makes $25 per hour. Which equation models the situation?

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bit. $^{}$ ly/3a8Nt8n

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3 years ago

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34 is 50% of what number?

lora16 [44]

In other words, you know that 50 percent of a number is 34 and you want to know what that initial number is.

To solve this problem you multiply 34 by 100 and then divide the total by 50 as follows:

(34 x 100) / 50

When we put that into our calculator, we get the following answer:

68

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3 years ago

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. The function V (s)=30.094s can be used to find the

balu736 [363]

Answer:

6...9...

Step-by-step explanation:

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3 years ago