Question

Evaluate the geometric series. Round to the nearest hundredth. Please help me!!!

Answer 1

Answer:

62.34

Step-by-step explanation:

Substitute n = 0 to n = 5 into the expression and sum the terms, that is

3 [ $(\frac{3}{2}) ^{0}$  + $(\frac{3}{2}) ^{1}$ + $(\frac{3}{2}) ^{2}$ + $(\frac{3}{2}) ^{3}$ + $(\frac{3}{2}) ^{4}$ + $(\frac{3}{2}) ^{5}$ ]

= 3 [ 1 + $\frac{3}{2}$ + $\frac{9}{4}$ + $\frac{27}{8}$ + $\frac{81}{16}$ + $\frac{243}{32}$ ]

= 3( $\frac{665}{32}$ )

= 3 × 20.781

= 62.34 ( to the nearest hundredth )