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Savatey [412]
3 years ago
11

Evaluate the geometric series. Round to the nearest hundredth. Please help me!!!

Mathematics
1 answer:
kari74 [83]3 years ago
5 0

Answer:

62.34

Step-by-step explanation:

Substitute n = 0 to n = 5 into the expression and sum the terms, that is

3 [ (\frac{3}{2}) ^{0}  + (\frac{3}{2}) ^{1} + (\frac{3}{2}) ^{2} + (\frac{3}{2}) ^{3} + (\frac{3}{2}) ^{4} + (\frac{3}{2}) ^{5} ]

= 3 [ 1 + \frac{3}{2} + \frac{9}{4} + \frac{27}{8} + \frac{81}{16} + \frac{243}{32} ]

= 3( \frac{665}{32} )

= 3 × 20.781

= 62.34 ( to the nearest hundredth )

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What is the range of the function below in set builder notation? y=|x-3|
Kisachek [45]

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This translates to "y is any real number such that it is 0 or larger".

The reasoning is that the result of any absolute value function is either 0 or positive. In other words, we'll never get a negative result of an absolute value function. This is due to how absolute value represents distance. Negative distance does not make sense.

So if y = |x-3| then y = 0 is the smallest output possible. We could have any positive output we want.

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4 0
3 years ago
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natka813 [3]

Answer:

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
Can someone explain how to do this and add the formula please
lisabon 2012 [21]

Answer:

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Step-by-step explanation:

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kondor19780726 [428]

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Letter C is the correct answer!

Hope this helps! ;)

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3 years ago
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Dmitriy789 [7]

Answer:

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Hope it's correct!

4 0
3 years ago
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