Answer:
B = (5, 1).
Step-by-step explanation:
From the formula for the midpoint of a line :-
(-1 + x)/2 , (5 + y)/2 = (6/2, 6/2) where x and y are the coordinates of B.
so (-1 + x)/2 = 6/2
-1 + x = 6
x = 5.
and (5 + y)/2 = 6/2
5 + y = 6
y = 1.
Answer:
223hjvfcnv5ctdydxrxr hgho8
A turning point occurs when the velocity is equal to zero, but the acceleration is not equal to zero.
t(x)=(x+5)^3+7
dt/dx=3(x+5)^2
d2t/dx2=6(x-5)
dt/dx=0 only when x=-5
However, since d2t/dx2(-5)=0, this point is an inflection point, not a turning point.
So there is no turning point for this function.
Now in this problem, it is even easier than the above to show that there is no turning point. A turning point by definition is when the derivative or velocity changes sign. Since in this case v=3(x+5)^2, for any value of x, v≥0, and thus never becomes negative, so it never changes from a positive to negative velocity because velocity in this instance is a squared function.
