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daser333 [38]
3 years ago
13

What is the quotient (x3 – 3x2 + 3x – 2) ÷ (x2 – x + 1)?

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
5 0

-2/x+1

the / is a fraction symbol xxx

Maurinko [17]3 years ago
5 0
The answer is x-2, just do synthetic division or long division
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5 kilometers 745 decimeters = how many<br> decimeters
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5 kilometers = 5000 decimeters if that answers your question sorry ...
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3 years ago
Given: ABCD is a ∥-gram; DE ∩ AB =F <br> Prove: △ADF∼△CDE
Vedmedyk [2.9K]

Answer:

By AA similarity

Step-by-step explanation:

We have been given that ABCD is a parallelogram

So, by the property of parallelogram AB ||CD and FD is cutting the line BC

Hence, FD is transverse line. In transverse line alternate angles are equal.

Therefore, ∠AFD=∠EDC  (alternate interior angles)

And ∠FAD=∠ECD (opposite angles in parallelogram)

Therefore, by AA similarity △ADF∼△CDE

5 0
3 years ago
Two cables support a 800​-lb ​weight, as shown. Find the tension in each cable.
jeka94

Answer:

  • 892 lb (right)
  • 653 lb (left)

Step-by-step explanation:

The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...

  Rcos(45°) +Lcos(75°) = 800

  Rsin(45°) -Lsin(75°) = 0

Solving these equations by Cramer's Rule, we get ...

  R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))

     = 800sin(75°)/sin(120°) ≈ 892 . . . pounds

  L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds

The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.

_____

This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...

  (right, left) = w/sin(α+β)×(sin(β), sin(α))

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2 years ago
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8 0
2 years ago
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Solve for x<br> 5x + 6 &lt; 3x + 7
Illusion [34]

Answer:

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8 0
3 years ago
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