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kap26 [50]
4 years ago
12

A liner graph in the coordinate plane that has no breaks in it is

Mathematics
1 answer:
crimeas [40]4 years ago
6 0
Your answer would be: Continuous Graph

Hope this helps! God bless! :))
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If you can answer this question please do it as soon as you can.
miv72 [106K]

9514 1404 393

Answer:

  • 6.045×10^40 ergs
  • 1.8×10^-2 mm

Step-by-step explanation:

A) Your scientific or graphing calculator can tell you the product:

  (3.9×10^33 erg/s)(1.55×10^7 s) = 6.045×10^40 ergs

__

B) 10^2 mm is 100 mm, about 4 inches, so 1.8×10^2 mm is about 7 inches. This is somewhat larger than the diameter of a human hair (and about the same size as the diameter of a human <em>head</em>).

1.8×10^-2 mm = 18 μm is a more reasonable estimate of hair diameter

(The range of hair diameters is reportedly about 17 to 181 μm, so the given dimension is on the low end.)

8 0
3 years ago
Which of these angles can replace x in tan (x)?
Alex17521 [72]

Answer:

C. φ

Step-by-step explanation:

tan \phi \:  =  \frac{6}{5}  \\  \\ tan x \:  =  \frac{6}{5}  \\  \implies \: x =  \phi

Thus \Phi can replace x

6 0
3 years ago
Sarah started with 50 dollars in her bank account. Each month, she puts 25 more dollars in her account. The amount of money in d
Basile [38]


D=25m+50

D=(25)(8)+50

D=200+50

D=250

There will be $250 after 8 months.

5 0
3 years ago
Read 2 more answers
Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =
irga5000 [103]

Answer:  The required solution is y=50e^{0.1386t}.

Step-by-step explanation:

We are given to solve the following differential equation :

\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.

From equation (i), we have

\dfrac{dy}{y}=kdt.

Integrating both sides, we get

\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]

Also, the conditions are

y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50

and

y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.

Thus, the required solution is y=50e^{0.1386t}.

8 0
3 years ago
Read 2 more answers
Solve the system by substitution. Check your solution.
zvonat [6]
B. (9,126)

<span>y + 18 = 16x
=>y=16x-18 
0.5x + 0.25y = 36 (multiply both sides by 4)
=>2x+y = 144
Substitute y=16x-8

=>2x+16x-8=144
=>18x=152
=>x=152/18=9 
y=16x-18
=>y=16(9)-18
=>y=144-18=126 
Answer: x=9 and y=126</span>
4 0
3 years ago
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