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kap26 [50]
4 years ago
12

A liner graph in the coordinate plane that has no breaks in it is

Mathematics
1 answer:
crimeas [40]4 years ago
6 0
Your answer would be: Continuous Graph

Hope this helps! God bless! :))
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Round 512,162 and 84,097 to the nearest ten
bekas [8.4K]
First one is 512,160 and the second is 84,100
6 0
4 years ago
Find the nonpermissable replacement for the variable in this expression 3x over 5x+2
kotegsom [21]
5x + 2 is a denominator.
A denominator cannot equal zero since division by zero is undefined.
Set the denominator equal to zero and solve for x to find which value of x makes the denominator zero.

5x + 2 = 0

5x = -2

x = -2/5

The non-permissible replacement for the variable is -2/5.
5 0
4 years ago
Line m has a slope of 9/4. Line n is perpendicular to m. What is the slope of line n?
Nadusha1986 [10]

Answer:

-4/9

Step-by-step explanation:

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4 0
3 years ago
What is the value of x in the following equation? 2(x-3)+3=6x-5<br> x=2<br> x=-2<br> x=1/2<br> x=4
creativ13 [48]

x=1/2

don't mind the dirty white board lol

6 0
2 years ago
Read 2 more answers
Darren wants to estimate the mean age in a population of trees. He'll sample nnn trees and build a 90\%90%90, percent confidence
Alchen [17]

Using the z-distribution, as we have the standard deviation for the population, it is found that the smallest sample size required to obtain the desired margin of error is of 77.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

The margin of error is given by:

M = z\frac{\sigma}{\sqrt{n}}

In this problem, we have that the parameters are given as follows:

M = 3, z = 1.645, \sigma = 16.

Hence, solving for n, we find the sample size.

M = z\frac{\sigma}{\sqrt{n}}

3 = 1.645\frac{16}{\sqrt{n}}

3\sqrt{n} = 1.645 \times 16

\sqrt{n} = \frac{1.645 \times 16}{3}

(\sqrt{n})^2 = \left(\frac{1.645 \times 16}{3}\right)^2

n = 76.97

Rounding up, the smallest sample size required to obtain the desired margin of error is of 77.

More can be learned about the z-distribution at brainly.com/question/25890103

4 0
2 years ago
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