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OlgaM077 [116]
2 years ago
12

Given that Cos0=5/13,find a)Tan0,b)Sin0,c)Sec0,d)Co sec0,e)Cot0,​

Mathematics
1 answer:
aliina [53]2 years ago
4 0

Step-by-step explanation:

cos 0=5/13. B/H

p=√h2 - b2

= √13 square -5 square

=√169 -25

=√144

=12 Ans

Tan0=p/b =12/5. , sin0=p/h =12/13,. sec0= h/b =13/5 ,. Co sec0 =h/p =13/12 , cot0 =b/p=5/12

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A bowl has 8 green grapes and 15 red grapes. Henry randomly chooses a grape, eats it, and then chooses another grape. What is th
Dmitry_Shevchenko [17]

Answer:

About 41.5%

Step-by-step explanation:

<em>Given:</em>

<em>A bowl has 8 green grapes and 15 red grapes. Henry randomly chooses a grape, eats it, and then chooses another grape. </em>

<em>To Find:</em>

<em>What is the probability that both grapes are red?</em>

<em>Answer choices:</em>

<em>about 39.7% </em>

<em>about 41.5%</em>

<em> about 42.5% </em>

<em>about 44.5%</em>

<em>Solution:</em>

<em>Since, there are 8 green grapes and 15 red grapes, the total number of grapes is 23 . </em>

<em>As the red grapes are 15.. </em>

<em>Thus, </em>

<em>The probability of choosing a red grape the first time is 15/23.</em>

<em>Because out of the total 23 grapes only 15 were red grape.</em>

<em> The probability of choosing the red grape the second time will be 14/22. Because the number of red grapes has already decreased by one and so is the total number of grapes after first choice</em>

<em>Hence, the probability of choosing or eating two red grapes will be :</em>

<em>15/23×14/22 </em>

<em>=105/253 </em>

<em>=0.415</em>

<em>= 41.5% </em>

<em>Therefore, the probability that both grapes are red is about 41.5%</em>

<u><em>Kavinsky</em></u>

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1 year ago
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Answer:

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Then you have to make (x- 3/4) = 0 and (x +2 ) = 0

When you develop x - 3/4 = 0 you get 4x -3 = 0, which means that 4x - 3 is a factor. The other factor is directly x + 2.

Answer: option b: (4x -3)(x + 2)
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