Answer:
(-2,-1)
Step-by-step explanation:
y=2x+3
y=3x+5
so y=y
then:
2x+3=3x+5
3-5= 3x-2x
-2= X
x=-2
Answer:
Part A) 
Part B) 
Part C) 
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form
or
Let
x -----> the number of workers
y ----> the number of pieces made
In this problem
The relation between the variables x and y represent a direct variation (proportional variation)
so
For x=16, y=40
Find the value of the constant of proportionality k
substitute the values

The linear equation is equal to

Part A) How many workers are needed to make 20 pieces
For y=20 pieces
substitute in the linear equation


Part B) How many workers are needed to make 25 pieces
For y=25 pieces
substitute in the linear equation


Part C) How many workers are needed to make 100 pieces
For y=100 pieces
substitute in the linear equation


Answer:
5
Step-by-step explanation:
12+12+12= 36
36-7= 29
3+3+3=9
29-9=20
20÷4=5
Answer:
Part A: A ratio of 2:1 means that he uses<u><em> </em></u><u><em>2 cups of yellow paint for each cup of blue paint.</em></u>
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Part B: The ratio of yellow to blue is 2:1 = 2/1. So, if for 2 yellow is 1 blue, then for 1 yellow is x:
2/1 = 1/x
x = (1*1) / 2
x = 1/2
<u><em>For each cup of yellow paint, Greg should add 1/2 cup of blue paint.</em></u>
<u><em></em></u>
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Part C: 6 cups cost $54, then 1 cup cost:
54 / 6 = 9
<u><em>The price per cup of yellow paint is $9.</em></u>
<u><em></em></u>
<h3>
Answer: Approximately 6.58 years old</h3>
The more accurate value is 6.57881347896059, which you can round however you need. I picked two decimal places.
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Explanation:
Let's pick a starting value of the car. It doesn't matter what the starting value, but it might help make the problem easier. Let's say A = 1000. Half of that is 1000/2 = 500.
So we want to find out how long it takes for the car's value to go from $1000 to $500 if it depreciates 10% per year.
The value of r is r = 0.10 as its the decimal form of 10%
t is the unknown number of years we want to solve for
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y = A(1 - r)^t
500 = 1000(1 - 0.1)^t
500 = 1000(0.9)^t
1000(0.9)^t = 500
0.9^t = 500/1000
0.9^t = 0.5
log( 0.9^t ) = log( 0.5 )
t*log( 0.9 ) = log( 0.5 )
t = log( 0.5 )/log( 0.9 )
t = 6.57881347896059
Note the use of logs to help us isolate the exponent.