The second one is the only equivalent equation. Simply plug in each variable in each equation. And compare!
Answer:
25 is the answer.
Step-by-step explanation:
Given the following functions:
![\begin{gathered} f(x)=x^2 \\ g(x)=3x-1 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20f%28x%29%3Dx%5E2%20%5C%5C%20g%28x%29%3D3x-1%20%5Cend%7Bgathered%7D)
To compose then, is basically use the inside function as the argument.
![f(g(x))=f(3x-1)](https://tex.z-dn.net/?f=f%28g%28x%29%29%3Df%283x-1%29)
If we call '3x-1' as 'u'
We know the following
![\begin{gathered} f(u)=u^2 \\ u=3x-1\Rightarrow f(3x-1)=(3x-1)^2 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20f%28u%29%3Du%5E2%20%5C%5C%20u%3D3x-1%5CRightarrow%20f%283x-1%29%3D%283x-1%29%5E2%20%5Cend%7Bgathered%7D)
And this is our answer.
The formula for finding the circumference of a circle is
(where d is the diameter). So, simply plugging in 622 mm for <em>d </em>and 3.14 for pi, we find that c = 622 * 3.14 = 1953.08 mm.