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3 years ago

Expand.If necessary, combine like terms.(2+7x)(2-7x)stuck? Watch a vide

Mathematics

2 answers:

m_a_m_a [10]3 years ago

8 0

Answer:4-49x^2

Step-by-step explanation:

2^2-(7x)^2= given ans

scoray [572]3 years ago

3 0

Answer:

$\boxed{\bold{-49x^2+4}}$

Explanation:

Apply Difference of Two Squares Formula: $\bold{\left(a+b\right)\left(a-b\right)=a^2-b^2}$

$\bold{a=2,\:b=7x}$

= $\bold{2^2-\left(7x\right)^2}$

Simplify $\bold{2^2-\left(7x\right)^2: \ -49x^2+4}$

$\boxed{\bold{-49x^2+4}}$

You might be interested in

Identify the linear term in the function of y = 2x2 − 5x − 12

MakcuM [25]

Answer:

The linear term is -5x

Step-by-step explanation:

The linear term is the term that has the degree equal to 1.

The given function is

y = 2x^2 − 5x − 12

here 2x^2 = quadratic term i.e having degree 2

-5x = linear term i.e having degree 1

-12 = constant

so, The linear term is -5x

4 0

3 years ago

Select the solution to the graph from the following points. Select all that apply.

stellarik [79]

Answer:

The solutions are:

(-15 , -4) ⇒ 1st

(3 , 2) ⇒ 3rd

(21 , 8) ⇒ 5th

Step-by-step explanation:

To find the solution of the graph let us make the equation of the line by using any two points on the line

The form of the linear equation is y = m x + b, where

m is the slope of the line
b is the y-intercept (value y at x = 0)

The formula of the slope is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

From the figure

∵ The line passes through points (-3 , 0) and (0 , 1)

- Find the slope of the line

∴ $m=\frac{1-0}{0--3}=\frac{1}{3}$

- Substitute the value of m in the form of the equation

∴ y = $\frac{1}{3}$ x + b

∵ b is the value of y at x = 0

∵ y = 1 at x = 0 ⇒ y-intercept

∴ b = 1

∴ y = $\frac{1}{3}$ x + 1

Lets substitute the x-coordinate of each point to find the y-coordinate, if the y-coordinate is equal to the y-coordinate of the points, then the point is a solution

Point (-15 , -4)

∵ x = -15

∴ y = $\frac{1}{3}$ (-15) + 1

∴ y = -5 + 1 = -4 ⇒ same value of the point

∴ (-15 , -4) is a solution

Point (-6 , 1)

∵ x = -6

∴ y = $\frac{1}{3}$ (-6) + 1

∴ y = -2 + 1 = -1 ⇒ not the same value of the point

∴ (-6 , 1) is not a solution

Point (3 , 2)

∵ x = 3

∴ y = $\frac{1}{3}$ (3) + 1

∴ y = 1 + 1 = 2 ⇒ same value of the point

∴ (3 , 2) is a solution

Point (12 , 9)

∵ x = 12

∴ y = $\frac{1}{3}$ (12) + 1

∴ y = 4 + 1 = 5 ⇒ not the same value of the point

∴ (12 , 9) is not a solution

Point (21 , 8)

∵ x = 21

∴ y = $\frac{1}{3}$ (21) + 1

∴ y = 7 + 1 = 8 ⇒ same value of the point

∴ (21 , 8) is a solution

6 0

3 years ago

Which ordered pairs are solutions to the inequality 2x+y>−4?

hichkok12 [17]

we will proceed to resolve each case to determine the solution

we have

$2x+y>-4$

$y>-2x-4$

we know that

If an ordered pair is the solution of the inequality, then it must satisfy the inequality.

case a) $(5,-12)$

Substitute the value of x and y in the inequality

$-12>-2*5-4$

$-12>-14$ ------> is True

therefore

the ordered pair $(5,-12)$ is a solution of the inequality

case b) $(-3,0)$

Substitute the value of x and y in the inequality

$0>-2*-3-4$

$0>2$ ------> is False

therefore

the ordered pair $(-3,0)$ is not a solution of the inequality

case c) $(-1,-1)$

Substitute the value of x and y in the inequality

$-1>-2*-1-4$

$-1>-2$ ------> is True

therefore

the ordered pair $(-1,-1)$ is a solution of the inequality

case d) $(0,1)$

Substitute the value of x and y in the inequality

$1>-2*0-4$

$1>-4$ ------> is True

therefore

the ordered pair $(0,1)$ is a solution of the inequality

case e) $(4,-12)$

Substitute the value of x and y in the inequality

$-12>-2*4-4$

$-12>-12$ ------> is False

therefore

the ordered pair $(4,-12)$ is not a solution of the inequality

Verify

using a graphing tool

see the attached figure

the solution is the shaded area above the line

The points A,C, and D lies on the shaded area, therefore the ordered pairs A,C, and D are solution of the inequality

7 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B75%5D%7B6000%7D%20" id="TexFormula1" title=" \sqrt[75]{6000} " alt=" \sqrt[75]{60

PilotLPTM [1.2K]

$\sqrt[75]{6000} =1.12$

7 0

3 years ago

If F(x) =5x/3 +5

victus00 [196]

Answer:

$f^{-1}(x)=\frac{3(x-5)}{5}$

Step-by-step explanation:

$f(x)=y=\frac{5x}{3}+5\\y-5=\frac{5x}{3}\\3(y-5)=5x\\x=\frac{3(y-5)}{5}\\ => f^{-1}(x)=\frac{3(x-5)}{5}$

7 0

3 years ago

Expand.If necessary, combine like terms.(2+7x)(2-7x)stuck? Watch a vide​

Expand.If necessary, combine like terms.(2+7x)(2-7x)stuck? Watch a vide