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wariber [46]
3 years ago
15

Line EF has an equation of a line y = −2x + 7. Which of the following could be an equation for a line that is perpendicular to l

ine EF?
Answer Choices:

y = 2x - 3

y = 1/2x - 3

y = -2x - 3

y = -1/2x - 3
Mathematics
1 answer:
Ksju [112]3 years ago
3 0

Answer:

  y = 1/2x -3

Step-by-step explanation:

The slope of the given line is the x-coefficient: -2. The slope of the perpendicular line is the negative reciprocal of this:

  -1/(-2) = 1/2

The only answer choice with a slope of 1/2 is ...

  y = 1/2x -3

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Lydia earned $9.75 per hour last summer. She worked 25 hours a week. About how much did she earn in 10 weeks.
Goryan [66]
Well $9.75 times 25 hours is $243.75.

Then you take that and multiply it by 10.

So she earned $2,437.5
5 0
3 years ago
You are given g(x)=4x^2 + 2x and
Strike441 [17]

Answer:

324

Step-by-step explanation:

Given:

g(x)=4x^2+2x\\ \\f(x)=\int\limits^x_0 {g(t)} \, dt

Find:

f(6)

First, find f(x):

f(x)\\ \\=\int\limits^x_0 {g(t)} \, dt\\ \\=\int\limits^x_0 {(4t^2+2t)} \, dt\\ \\=\left(4\cdot \dfrac{t^3}{3}+2\cdot \dfrac{t^2}{2}\right)\big|\limits^x_0\\ \\=\left(\dfrac{4t^3}{3}+t^2\right)\big|\limits^x_0\\ \\= \left(\dfrac{4x^3}{3}+x^2\right)-\left(\dfrac{4\cdot 0^3}{3}+0^2\right)\\ \\=\dfrac{4x^3}{3}+x^2

Now,

f(6)\\ \\=\dfrac{4\cdot 6^3}{3}+6^2\\ \\=288+36\\ \\=324

4 0
3 years ago
{ PLEASE ANSWER QUICKLY, PROBLEM DUE ASAP } The functions f(x) and g(x) are defined below. Which expression is equal to f(x) + g
8090 [49]

Answer:

Option C. 2x + 20 / x² + 6x – 40

Step-by-step explanation:

f(x) = x + 16 / x² + 6x – 40

g(x) = 1 / x + 10

To find f(x) + g(x), please refer to the attached photo.

7 0
3 years ago
Please help I have to turn this in by the end of the night
Svetllana [295]

Answer:

C is the corner of the table

7 0
3 years ago
Read 2 more answers
I need help NOW!!!!!!!!!!!
weqwewe [10]

Its just 30x60=1800...right?

7 0
3 years ago
Read 2 more answers
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