See attachment for the drawing of the perpendicular at a point c on line ab such the ac = 3.5 cm
<h3>How to draw the perpendicular at a point c on line ab such the ac = 3.5 cm?</h3>
The given parameters are:
Length of segment AB = 7 cm
Also, we have:
Point C is located on line segment AB
This means that:
Length of segment AC = Length of segment BC = 3.5 cm
When represented on a line segment, we have:
A C B
See attachment for the drawing of the perpendicular at a point c on line ab such the ac = 3.5 cm
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Answer:
Step-by-step explanation:
new length=15+x
width=19+x
then area=(15+x)×(19+x)=285+15x+19x+x²=x²+34x+285 ft²
original area=15×19=285 ft²
then 285+98=x²+34x+285
or
x²+34x-98=0
x²+34x+17²=98+17²
(x+17)²=98+289=387
x+17=√387=3√43
x=3√43-17 ft
a) 3(-2) + 4(3) = -6 + 12 = 6
b) 2(-2) -3(3) +5 = -4 -9 + 5 = -8
c) 4(-2) -(3) = -8 -3 = -11
d) -(-2) -2(3) = 4 -6 = -2
e) (1/2)(-2) +(3) = -1 +3 = 2
f) (2/3)(3) -(1/2)(-2) = 2 + 1 = 3
Answer:G
Step-by-step explanation:
4/9 times 2/8= 1/9