Answer:
Step-by-step explanation:
Step 1: Write out limit
Step 2: Evaluate
(2 + 1)(3(2)² - 9)
3(3(4) - 9)
3(12 - 9)
3(3)
9
Answer:
6.10%
Step-by-step explanation:
For every round since we are choosing with equal probability, then the probability of choosing from either of the bags is 1/2
Here, this scenario is only possible when a particular bag has been chosen 10 times and the other bag has been chosen 6 times ( meaning a particular bag has been emptied and for a particular bag to be emptied, all of its content would have been picked)
Now on the 17th trial, an empty bag is chosen
Therefore the required probability will be;
16C0 * (1/2)^10 * (1/2)^6 * 1/2 = 0.0610 = 6.1%
Answer:
Therefore the Correct option is First one
SAS, ∠A ≅ ∠C, AB ≅ CB , ∠ABD ≅ ∠CBD
.
Step-by-step explanation:
Given:
∠BDA ≅ ∠BDC
AD ≅ CD
TO Prove
ΔADB ≅ ΔCDB
Proof:
In ΔADB and ΔCDB
AD ≅ CD ....……….{Given}
∠BDA ≅ ∠BDC …………..{Given}
BD ≅ BD ....……….{Reflexive Property}
ΔADB ≅ ΔCDB ….{By Side-Angle-Side Congruence Postulate}
∴ ∠A ≅ ∠C ......{Corresponding Parts of Congruent Triangle are Congruent}
AB ≅ CB ......{Corresponding Parts of Congruent Triangle are Congruent}
∠ABD ≅ ∠CBD {Corresponding Parts of Congruent Triangle are Congruent}
Answer: 44
Step-by-step explanation:
Answer:
31/5
Step-by-step explanation:
b c you factor is 620:2^2.5.
