What are the zeros of the function? f(x)=x2+17x+72

1 answer:

4 0

In order to find zeroes of a function, we will probably want to use our quadratic formula.

-b±√b^2-4(a)(c)/2a

If we know our values, we can plug it in.

Our values:

A=1 (Since there is no number in front of x, it is an assumed 1)
B=17
C=72

Now, We can plug it into our formula.

BE SURE TO PUT PARENTHESIS AROUND ALL TERMS!

-(17)±√(17)^2-4(1)(72)/2(1)

Now we can type it into a calculator!

When we plug it into the formula. It gives us two real solutions (or zeroes) which are represented as:

-8 & -9.

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Which number is an irrational number? A. B. C. D.

Ivahew [28]

There’s nothing so let’s just go with C

6 0

3 years ago

Which expression is equivalent to (r Superscript negative 7 Baseline) Superscript 6? r Superscript 42 StartFraction 1 Over r Sup

vodomira [7]

Power rule of exponents says that the power of the power of a exponent is equal to the multiplying both the powers. The expression which is equal to the given expression is,

$\dfrac{1}{(r)^{42}}$

The option B is the correct option.

Given information-

The given expression in the problem is,

$[(r)^{-7}]^5$

<h3>Power rule of exponents</h3>

Power rule of exponents says that the power of the power of a exponent is equal to the multiplying both the powers.

Suppose<em> </em><em>x</em> is a number with power <em>a. </em>The power is power of the power of number <em>x. </em>Then by the power rule of the exponents,

$(x^a)^b=x^{ab}$

Using the power rule of the exponents given expression can be written as,

$[(r)^{-7}]^6=(r)^{-7\times 6} 
$

$[(r)^{-7}]^6=(r)^{-42}$

<h3>Negative exponents rule</h3>

Negative exponents rule says that when a power of a number is negative, then write the number in the denominator with the same power with positive sign.Thus,

$[(r)^{-7}]^6=\dfrac{1}{(r)^{42}}$