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vitfil [10]
3 years ago
10

What is the minimum and maximum of the picture

Mathematics
1 answer:
LiRa [457]3 years ago
6 0
The coordinates of the maximum and the minimum are:
maximum(1 , 8)

minimum(-2 , -4)

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Simplify completely:
tigry1 [53]
Exponental law

( \sqrt{x}) times ( \sqrt{n} )= \sqrt{xn} so
√(81y^5)=√81 times √(y^5)
√81=9 or -9
√(y^5)=y^2 times√y
answer is 9y^2 times √y or -9y^2 times √y
4 0
3 years ago
Find the greatest common factor of 6w^3 and 5n^4
scZoUnD [109]
Hi there!

• Greatest Common Factor :-

GCF is th' greatest factor that divides two numbers.

To find the GCF of two numbers :-

→ List the prime factors of each number.
→ Multiply those factors both numbers have in common.

Accr'ding to the question :-

5n⁴ = 5 × n × n × n × n × 1
6w³ = 2 × 3 × w × w × w × 1

Greatest Common Factor [ 5n⁴, 6w³ ] = 1

~ Hope it helps!
7 0
3 years ago
A food company originally sells cereal in boxes with dimensions 25 cm by 14 cm by 10 cm. To make more profit, the company decrea
hjlf

Answer:

1.75 cm

Step-by-step explanation:

We are given that the dimensions of the box as 25 cm by 14 cm by 10 cm.

Now, to increase the profit, the dimensions of the box by 'x' cm.

Thus, the new dimensions are (25-x) cm by (14-x) cm by (10-x) cm.

Further, it is given that the volume of the new box is 2,208 cm^{3}

As, Volume of the box = Length × Breadth × Height

i.e. 2208 = (25-x) × (14-x) × (10-x)

i.e. 2208 = (25-x) \times (140-24x-x^{2})

i.e. 2208=x^{3}-x^{2}-740x+3500

i.e. x^{3}-x^{2}-740x+1292=0

On solving this cubic equations, we get that, the solutions are x = 27.6, x = 1.75 and x = 26.8.

Since, the dimensions 25 cm by 14 cm by 10 cm are reduced by x cm.

Thus, if x = 27.6 or x = 26.8, then (10-x) = -17.6 or -16.8, which cannot be possible. So, x = 1.75 cm.

Hence, the dimensions were decreased by 1.75 cm.

3 0
3 years ago
Read the ques
Dafna11 [192]

Answer:

0.25feet

Step-by-step explanation:

The equation is not well written. Let the equation of the height be modelled as;

h = -16d²+8d+4

The velocity of the ball is zero at its maximum height.

Velocity = change in displacement/time

v = dh/dd

Differentiate

v = -32d+8

Since dh/dd = v = 0

0 = -32d+8

Add 32d to both sides

0+32d = 8

32d = 8

Divide both sides by 32

32d/32 = 8/32

d = 1/4

d = 0.25feet

Hence the maximum height of the tennis ball is 0.25feet

Note that the modeled equation was assumed. You can apply the same calculation to any equation given

3 0
3 years ago
In Mathematics what is 4y+2=x+8
zhannawk [14.2K]
1.) Isolate a variable.
2.) Subsitube
3.) then solve for other varible.
8 0
3 years ago
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